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harina [27]
4 years ago
8

Consider the equation below. Na+ + Cl– Right arrow. NaCl Which statement best describes the relationship between the substances

in the equation? The number of sodium ions is equal to the number of formula units of salt. The number of sodium ions is less than the number of chloride ions. The number of chloride ions is less than the number of formula units of salt. The number of sodium ions is two times the number of formula units of salt.
Chemistry
1 answer:
Naddik [55]4 years ago
3 0

Answer:

a)  The number of sodium ions is equal to the number of formula units of salt.

Explanation:

In the given reaction of NaCl

i.e. Na+ + Cl-  →NaCl.

Number of sodium ions = Number of chloride ions = number of  formula units of salt. Hence, the only correct option among all is, the number of sodium ions is equal to the number of formula units of salt. Rest all options are incorrect.

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The density of a gas is 1.35 L what is the volume of the gas when the mass is 12.5 g
mart [117]

Answer:

<h2>9.26 L</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{12.5}{1.35}  \\  = 9.259259...

We have the final answer as

<h3>9.26 L</h3>

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8 0
3 years ago
How many grams of sodium formate, NaCHO2, would have to be dissolved in 3.0 L of 0.12 M formic acid (pKa 3.74) to make the solut
kolbaska11 [484]

Answer:

Mass_{sodium\ formate}= 889.57\ g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:

pH=pK_a+log\frac{[salt]}{[acid]}

Given that:-

[Acid] = 0.12 M

Volume = 3.0 L

pKa = 3.74

pH = 5.30

So,  

5.30=3.74+log\frac{[sodium\ formate]}{0.12}

Solving, we get that:-

[Sodium formate] = 4.36 M

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,

Moles =Molarity \times {Volume\ of\ the\ solution}

So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles

Molar mass of sodium formate = 68.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

13.08\ mole= \frac{Mass}{68.01\ g/mol}

Mass_{sodium\ formate}= 889.57\ g

5 0
4 years ago
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