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tamaranim1 [39]
3 years ago
14

Particles are arranged in a crystal structure in a sample of

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
The answer is (4) Ag(s)

Solid Silver has a Face Centered Cubic crystal structure.

The remaining choices are gases (H2 & Ar) and liquid (Br). Liquids and gases do not form crystal structures as their atoms are loose.
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The gas in a 250. mL piston experiences a change in pressure from 1.00 atm to 4.45 atm. What is the new volume (in mL) assuming
Tju [1.3M]

Answer:

56.2 mL

Explanation:

Given data

  • Initial volume (V₁): 250 mL
  • Initial pressure (P₁): 1.00 atm
  • Final volume (V₂): ?
  • Final pressure (P₂): 4.45 atm

Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.00 atm × 250 mL/ 4.45 atm

V₂ = 56.2 mL

6 0
4 years ago
A 2.832 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 6.439 grams of CO2 and 2
strojnjashka [21]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is C_2H_2O_4  and C_6H_{12}O_2 respectively.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=6.439g

Mass of H_2O=2.636g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 6.439 g of carbon dioxide, \frac{12}{44}\times 6.439=1.756g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 2.636 g of water, \frac{2}{18}\times 2.636=0.293g of hydrogen will be contained.

  • Mass of oxygen in the compound = (2.832) - (1.756 + 0.293) = 0.783 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.756g}{12g/mole}=0.146moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.293g}{1g/mole}=0.293moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.783g}{16g/mole}=0.049moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.049 moles.

For Carbon = \frac{0.146}{0.049}=2.97\approx 3

For Hydrogen  = \frac{0.293}{0.049}=5.97\approx 6

For Oxygen  = \frac{0.049}{0.049}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is C_3H_{6}O_1=C_3H_6O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 116.2 g/mol

Mass of empirical formula = 58 g/mol

Putting values in above equation, we get:

n=\frac{116.2g/mol}{58g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(3\times 2)}H_{(6\times 2)}O_{(1\times 2)}=C_6H_{12}O_2

Thus, the empirical and molecular formula for the given organic compound is C_3H_6O and C_6H_{12}O_2 respectively.

7 0
3 years ago
Which of the following is the electron configuration of an excited atom that is likely to emit a quantum of energy?
Soloha48 [4]

Answer: 1s2 2s2 2p6 3s1 3p1

Explanation:

Excitation of an electron is an elevation in energy level of the valence electron above the ground state electron.

When an electron gains energy, usually the outermost electron it moves from a orbital of lower energy to a orbital of higher energy, the element is in an excited state.

The electron configuration of ground state of magnesium is 1s2 2s2 2p6 3s1 3p2, when it gains energy the electronic configuration is 1s2 2s2 2p6 3s1 3p1 the excited state of Magnesium this is because the last electron moves from the 3S orbital to a higher energy orbital 3P

7 0
3 years ago
Which measurement is a vector?
Andreas93 [3]
To measure a vector is to characterize both its direction (in one form or another) and a value (usually, a number). For example, velocity of a car moving on the road is a vector and, to measure it, we have to specify its direction (e.g. North or at angle 20 degrees from the North) and value (e.g. 40 m/sec).
4 0
3 years ago
Organic chemistry is the study of compounds containing
Darya [45]
It's carbon. All organic compounds contain carbon
5 0
3 years ago
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