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tamaranim1 [39]
3 years ago
14

Particles are arranged in a crystal structure in a sample of

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
The answer is (4) Ag(s)

Solid Silver has a Face Centered Cubic crystal structure.

The remaining choices are gases (H2 & Ar) and liquid (Br). Liquids and gases do not form crystal structures as their atoms are loose.
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How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?
allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

 

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

 

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

 

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

<span>volume Na2S = 0.0212 L = 21.2 mL</span>

6 0
3 years ago
What type of physical weathering is caused by the expansion of water?
skelet666 [1.2K]

Answer:

wedging

Explanation:

ice or frost wedging

6 0
2 years ago
An atom of 14 6 c carbon decays by gamma decay which atom is left after the decay
ladessa [460]
Answer is: carbon.

<span>During gamma emission the nucleus emits radiation without changing its composition, if for example have nucleus with six protons and six neutrons (carbon atom) and after gamma decay there is nucleus with six protons and six neutrons.
Gamma rays are the electromagnetic waves with the shortest wavelengths (1 pm), highest frequencies (300 EHz) and highest energy (1,24 MeV).</span>


7 0
3 years ago
Read 2 more answers
Stannum has a body centered tetragonal with lattice constant, a = b = 5.83A and c = 3.18A. If the atomic radius is 0.145 nm, det
Fed [463]

Answer:

the atomic packing factor of Sn is 0.24

Explanation:

a = b = 5.83A and c = 3.18A.

Volume of unit cell = a²c

= (5.83)² *  3.18 * 10⁻²⁴ cm³

= 1.08 * 10⁻²²cm³

Volume of atoms =

2 \times  \frac{4}{3} \pi r^3

(∴ BCC, effective number of atom is 2)

Volume of atoms =

2 * \frac{4}{3} *3.14*(0.145*10^-^7cm)^3

= 2.55*10⁻²³cm³

\text {Atomic packing factor}=\frac{\text {volume occupied by atom}}{\text {volume of unit cell }}

=\frac{2.55*10^-^2^3}{1.08*10^-^2^2} \\\\=0.24

<h3>therefore, the atomic packing factor of Sn is 0.24</h3>
4 0
3 years ago
Can someone please help me ANSWER this question down below?
julsineya [31]

This statement is true

4 0
3 years ago
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