Explanation:
MD: 242 364 7480
Ps: TYSON all can come for talking about
Answer:
Cooper and zinc if I remember right
Answer:
290 grams
Explanation:
Let's begin by writing the balanced chemical equations:
![C_{3}H_{8} +5O_{2} --->3CO_{2} +4H_{2}O](https://tex.z-dn.net/?f=C_%7B3%7DH_%7B8%7D%20%2B5O_%7B2%7D%20---%3E3CO_%7B2%7D%20%2B4H_%7B2%7DO)
Then we calculate the number of moles in 97g of propane.
n(propane)=![\frac{mass}{molarmass} =\frac{97g}{44.1g/mol}=2.1995mol](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolarmass%7D%20%3D%5Cfrac%7B97g%7D%7B44.1g%2Fmol%7D%3D2.1995mol)
According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.
n(carbon dioxide)= 2.1995mol*3 = 6.5985mol
mass(carbon dioxide) = moles * molar mass
= 6.5985 mol * 44.01 g/mol
= 290 grams
Answer: 40.3 L
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of
produces = 3 moles of
Thus 0.600 moles of
will produce=
of
Volume of
Thus 40.3 L of CO is produced.
Answer:
![m_{Co^{3+}}=0.563gCo^{3+}](https://tex.z-dn.net/?f=m_%7BCo%5E%7B3%2B%7D%7D%3D0.563gCo%5E%7B3%2B%7D)
Explanation:
Hello there!
In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:
![m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}](https://tex.z-dn.net/?f=m_%7BCo%5E%7B3%2B%7D%7D%3D2.34gCo%28NO_3%29_3%2A%5Cfrac%7B1molCo%28NO_3%29_3%7D%7B244.95%20gCo%28NO_3%29_3%7D%20%2A%5Cfrac%7B1molCo%5E%7B3%2B%7D%7D%7B1molCo%28NO_3%29_3%7D%20%2A%5Cfrac%7B58.93gCo%5E%7B3%2B%7D%7D%7B1molCo%5E%7B3%2B%7D%7D%20%5C%5C%5C%5Cm_%7BCo%5E%7B3%2B%7D%7D%3D0.563gCo%5E%7B3%2B%7D)
Best regards!