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Murrr4er [49]
3 years ago
13

How many moles of glucose molecules?​

Chemistry
1 answer:
muminat3 years ago
6 0

1 molecule of glucose contains 6 atoms of C, 12 atoms of H , and 6 atoms of 0.1 mole of glucose contains 6 moles of C atoms , 12 moles of H atoms , and 6 moles of O atoms .

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Oxidation number ofAl2S12O7
Savatey [412]

Answer:

-2? if wrong im sorry please tell me what I did that was incorrect ty  Explanation:

6 0
3 years ago
What is the pH of a 0.028M solution (pH= -log(M))<br><br> A) 3.56<br> B) 2.88<br> C) 1.55<br> D) 1
kupik [55]

Answer:

1.55

Explanation:

-log(M)=pH

- Hope that helps! Please let me know if you need further explanation.

4 0
3 years ago
How many grams are in 1.946 moles of nacl
Ilia_Sergeevich [38]

Answer:

113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

Number of moles of NaCl = 1.946mole

Unknown: mass of NaCl

Solution

To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:

                        Number of moles = \frac{mass}{molar mass}

To find the molar mass of NaCl:

                         the atomic mass of Na = 23g

                                atomic mass of Cl = 35.5g

                Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹

Mass of NaCl = Number of moles x molar mass of NaCl

Mass of NaCl = 1.946 x 58.5 = 113.8g

7 0
3 years ago
Which two types of consumers are known as “nature’s clean-up crew”? Why are they important?
NeTakaya

Fungus: Important because it breaks up several dead leaves, particles, etc, and puts nutrients back in the ground.

Carnivores: eat dead animals, no stinky rotten meat around.

3 0
3 years ago
Read 2 more answers
How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen?
Vsevolod [243]
 <span>This question asksyou to apply Hess's law. 
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C. 
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3 
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12 
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation. 
Then, 
6 H2(g) + 3O2 (g) --> 6H2O(l) delta H= -1716 kJ 
12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ 
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ 
______________________________________... 
2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ 
I hope this helps and my answer is right.</span>
4 0
3 years ago
Read 2 more answers
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