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garik1379 [7]
3 years ago
10

In which area of the diagram does the number −11 belong?

Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0
Integers and Rational Numbers, it is because if -11 is a Integer, it also has to be a Rational number. But your actual answer is Integers.
Dahasolnce [82]3 years ago
3 0

I can't see where the diagram is, but I've taken this test before so here is my answer; the correct answer choice is B) Integers. An Integer is any whole number on the negative side. If you look at the question, it's asking where -11 belongs. This number is a negative whole number, so it belongs in Integers.

Hope this helps!!

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Write the algebraic expression for the difference between the squares of two numbers.
V125BC [204]

The algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is

a² - b² = (a + b)(a - b).

An algebraic expression is a combination of terms, where the terms are separated using mathematical operators like plus (+), minus (-), multiply (*), and divide (/).

The terms are combinations of numerals and variables.

Variables are represented alphanumerically, which can hold any value as per the expression they are used in.

In the question, we are asked to write the algebraic expression for the difference between the squares of two numbers.

We assume the two numbers to be a and b respectively.

Thus, we are asked to write an expression for the difference between the square of a and square of b, that is, we are asked to write an expression for a² - b².

We know that a² - b² is an identity, which can be shown as (a + b)(a - b).

Thus, the algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is a² - b² = (a + b)(a - b).

Learn more about algebraic expressions at

brainly.com/question/2241589

#SPJ4

6 0
1 year ago
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
What is the sum of all of the perfect squares between
Nonamiya [84]

Answer:

(-138) is the answer.

Step-by-step explanation:

Perfect square numbers between 15 and 25 inclusive are 16 and 25.

Sum of perfect square numbers 16 and 25 = 16 + 25 = 41

Sum of the remaining numbers between 15 and 25 inclusive means sum of the numbers from 17 to 24 plus 15.

Since sum of an arithmetic progression is defined by the expression

S_{n}=\frac{n}{2}[2a+(n-1)d]

Where n = number of terms

a = first term of the sequence

d = common difference

S_{8}=\frac{8}{2} [2\times 17+(8-1)\times 1]

   = 4(34 + 7)

   = 164

Sum of 15 + S_{8} = 15 + 164 = 179

Now the difference between 41 and sum of perfect squares between 15 and 25 inclusive = 41-179

= -138

Therefore, answer is (-138).

7 0
2 years ago
CDEF is kite and m A. 14 <br> B. 56 <br> C. 28 <br> D. 62
brilliants [131]

Answer:

Step-by-step explanation:

56

8 0
2 years ago
If the diameter of a microscope's field is 0.12mm, how wide is an object that fills one-quarter of the field? (Explain how you'v
vlada-n [284]

Answer:.3mm

Step-by-step explanation:

5 0
3 years ago
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