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2 years ago

PLEASE HELP !!!!!!!Find y, such that ABC ~A DEF.

Mathematics

1 answer:

Lemur [1.5K]2 years ago

7 0

Use proportionals to find y.

$\frac{9}{18} = \frac{6}{y}$

Answer:y=12

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Least common multiple

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2 years ago

A car dealer has 8 rows of cars with 16 cars in each. In each of the first 3 rows, 6 are used cars. The rest of the cars new car

qwelly [4]

The answer is 110 because if you multiply 8•16=128 and 18 cars are used, you subtract 128-18 which is 110.

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3 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.

So $7\le k$ ; in set notation,

$\{k\mid 7\le k$

4 0

3 years ago

If angle 1 = 6n + 1 and angle 4 = 4n + 19, what is the angle 2?

kobusy [5.1K]

Angles 1 and 4 are alternate angles and thus have the same measurement. You will set their equations equal to each other and solve for the variable.

6n + 1 = 4n + 19

Subtract 1 and 4n from both sides to get variables on one side and constants on the other.

6n - 4n = 19 - 1

Combine like terms and solve for n.

2n = 18
n = 18 / 2
n = 9

Angles 1 and 2 are congruent as labeled in the graph.

So angle 2 is also 6n + 1

Plug in for 9 for n

6(9) + 1
54 + 1
55

Option C is your answer.

7 0

3 years ago

Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t

Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0

3 years ago