Two accounts earn simple interest. The balance y (in dollars) of Account A after x years can be modeled by y=10x 500. Account B
starts with $400 and earns 5% simple annual interest. Question I need help with: Which account has a greater principal, and how much greater is the principal? Which account has a greater annual interest rate, and how much greater is the annual interest weight?
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.
After k payments, the amount A still owed is
<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i,
= (P-Mq/i)(1+[i/q])k + Mq/i.
</span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)].
</span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i.
</span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]).
The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
Firstly do 16/4 which gives you 4 and then times that by 4 to give you 12 yards. Rinse and repeat this to find out how many yards are in each situation.
To find the amount of miles/gallon, we have 540 miles/18 gallons=30 miles/gallon. As we add 30 miles for every gallon, the amount of miles traveled is 30*x (e.g. if x is 1 then 0+30=30 and if x is 2 then 30+30 (2 times)=60) with x being the amount of gallons. For b, we just plug 12 in for x to get 20*12=360
