Which graph shows the solution set of...<br><br> Please help ASAP timed

The formula A=1w is used to calculate the area A of a rectangle surface using the length(l) and the width (w) of the surface whi

Sedaia [141]

A = lw

To isolate w, you have to divide l on both sides:
w = A/l

7 0

3 years ago

A square of side x is cut out of a larger square of side y. What is the area of the remaining

KonstantinChe [14]

Answer:

The area of the remaining figure is $y^2-x^2$

Step-by-step explanation:

<u>Area of the Square Shape</u>

Given a square of side length x, the area is calculated by the formula:

$A_x=x^2$

It's given a square of side x is cut out of a larger square of side y. Please refer to the image below.

The area of the square of side length y is:

$A_y=y^2$

The shaded area of the remaining figure is the difference between both areas:

$A=A_y-A_x$

$A=y^2-x^2$

The area of the remaining figure is $\mathbf{y^2-x^2}$

3 0

3 years ago

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago

Identify the property demonstrated. (7x3)^4 = 7^4 x 3^4

Vikki [24]

( 7 x 4 ) ^4 = 7^4 x 3^4
The rule is:
( a * b )^n = a^n * b^n
Answer:
D ) Power of a Product Property

6 0

3 years ago

Read 2 more answers

What is the minimum number of the data set shown on the box-and-whisker plot?

Dmitriy789 [7]

Hello there, and thank you for posting your question here on brainly.

Short answer: C. 9

Why?

Box and whisker plots are confusing, the line in the middle is the median, but we don't need to do that now. The dots on the lines outside of the box show the largest and the shortest number. The plotted point on the way left is your answer, the line plotted is 9.

[Mark as Brainliest!]

3 0

3 years ago

Which graph shows the solution set of... Please help ASAP timed