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hram777 [196]
3 years ago
11

Please help, I’m so confused :/

Mathematics
2 answers:
MakcuM [25]3 years ago
5 0
\tan x = \dfrac{\sin x}{\cos x}

\tan x = \dfrac{\frac{5}{13}}{\frac{12}{13}}

\tan x = \dfrac{5}{13} \times \dfrac{13}{12}

\tan x = \dfrac{5}{12}
Ratling [72]3 years ago
4 0
cos x = \frac{a}{h} , so a = 12, h = 13
sinx= \frac{o}{h}, so o = 5, h = 13
tanx = \frac{o}{a}
tanx = \frac{5}{12} 

Or 

tanx =  \frac{sinx}{cosx}
tanx =  \frac{ \frac{5}{13}}{ \frac{12}{13} }
tanx = \frac{5}{12} 
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I really need help a and b
Ivan

Using BEDMAS

a) 6+4(2+3)^2
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