Question

Please help, I’m so confused :/

Answer 1

$\tan x = \dfrac{\sin x}{\cos x}$

$\tan x = \dfrac{\frac{5}{13}}{\frac{12}{13}}$

$\tan x = \dfrac{5}{13} \times \dfrac{13}{12}$

$\tan x = \dfrac{5}{12}$

Answer 2

$cos x = \frac{a}{h}$ , so a = 12, h = 13
$sinx= \frac{o}{h}$, so o = 5, h = 13
$tanx = \frac{o}{a}$
$tanx = \frac{5}{12}$ 

Or 

$tanx = \frac{sinx}{cosx}$
$tanx = \frac{ \frac{5}{13}}{ \frac{12}{13} }$
$tanx = \frac{5}{12}$