Question

In how many ways can you arrange 4 different colored balls? 4,8,4!,3!,5!

Answer 1

Answer:

We can arrange 4 different colored balls in 24 ways.

Step-by-step explanation:

We have to find the number of ways in which we can arrange 4 different colored balls.

Firstly, we have to decide that either we use Permutation or we use Combination.

A Permutation is used when the order of arranging the numbers matters while on the other hand, a combination is used when the order of arranging the numbers doesn't matter.

So, in our question; the ordering matters to us as a ball which is placed in the first place can't be put again put in other places.

Number of ways of arranging 4 different colored balls = $^{4}P_4$

                     =  $\frac{4!}{(4-4)!}$          {$\because ^{n} P_r = \frac{n!}{(n-r)!}$ }

                     =  4! = $4 \times 3 \times 2\times 1$

                     =  24 ways

Hence, we can arrange 4 different colored balls in 24 ways.