It's false. It's a product so...
Derivative of the first TIMES the second PLUS derivative of second TIMES the first.
Derivative of the first (x^3) = 3x^2
Times the second = 3x^2 * e^x
Derivative of the second = e^x (remains unchanged)
Times the first = e^x * x^3
So the answer would be (3x^2)(e^x) + (e^x)(x^3)
which can be factorised to form x^2·e^x(3 + x)
Answer:
Step-by-step explanation:
Goal = > $2500
Amount raised = $700
Amount needed to raise = $2500 - 700 = $1800
Number of candy bars needed = x
Price of a candy bar = $1.50
1.5x > 1800
x > 1800 ÷ 1.5
x > 1200
Answer: They need to sell more than 1200 candy bars.
Answer:
<u>The correct answer is D. 12.50h</u>
Step-by-step explanation:
1. Let's review all the information given for answering the question correctly:
Price per hour of renting a rowboat at the lakeside hotel = US$ 12.50
Number of hours = h
Total cost = c
2. With the information in the table, which expression can be used to find c?
c = 12.50 * h
If h = 2 ⇒ c = 25; if h = 3 ⇒ c = 37.50.....if h = 6 ⇒ c = 75.
<u>The correct answer is D. 12.50h</u>
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
