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Alexxx [7]
4 years ago
5

$450 earns 5% per year. How much total in two years?

Mathematics
2 answers:
gavmur [86]4 years ago
5 0
$450 * 5% = 22.5

$450 + $22.5 = total earned for one year, which is $472.5

472.5 * 2 = total earned for two years, $945

Hope this helps,
~*Starry*
Alchen [17]4 years ago
4 0
It would be $855.00 because 5% of 450 is 22.5 and 450 - 22.5 is 427.5 then you times that by 2. i think 
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PSYCHO15rus [73]

Answer:

yes, $20.

Step-by-step explanation:

If you draw a line through the points it makes a straight line, so it is linear.  And you get $20 by dividing $100 per the 5 people.

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3 years ago
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
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The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
Paloma ran 3 3/4 miles around the school track. If each lap is 1/2 mile, how many laps did she run?
Ratling [72]

Answer:

9

Step-by-step explanation:

It is 9 because 1/2 goes into 3, 6 times, and then 3/4 divided by 1/2 is 1 1/2 so 1/2 goes into 3/4 1/12 times, so then figure out how mnay 1/2 is in 1 1/2 and youll get 3 so 6 plus 3 equals 9 :)

7 0
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bija089 [108]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
If EF = 2x+13, FG = 20, and EG = 71 what's the value of x​
klemol [59]

Answer:

<h2>x = 19</h2><h2></h2>

Step-by-step explanation:

|<----------------- 71 ----------------------->|

E-----------------------F---------------------G

       2x + 13                 20

find: x

EF + FG = DG

2x + 13 + 20 = 71

2x = 71 - 20 - 13

x = 38 / 2

x = 19

6 0
3 years ago
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