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2 years ago

4. Find the area: 23 m 5 m 379m² 389m² 74m² 5 m 18 m 6 m

Mathematics

1 answer:

Kipish [7]2 years ago

5 0

Answer: 379 meters squared

Step-by-step explanation:

Hello!

So, to calculate this area, we need to split it into 3 squares.

You can see that there is a big square, and on top of the big square, there are 2 smaller ones: one to the left and the other to the right.

Area of a square (in this case rectangle) = Lenght multiplied by width

We got 3 squares, if we calculate the area of each one's, we can add them together and get the total area of the irregular shape.

The first square will be the big one:

To get the length of the big square, we need to subtract 5 from 23.

Length of big square = 18 meters

And the width is also 18 meters

Area of the big square = 18 * 18 = 324 meters squared

Now, let's calculate the top left square's area.

That will be 5 meters * 5 meters.

Area of top left square = 25 meters squared.

Top right square's area = 6 meters * 5 meters.

Area of top right square = 30 meters squared

Now, we just gotta add them all up:

324 + 25 + 30 meters squared = 379 meters squared

Hope I Helped!

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4 years ago

Kristina used synthetic division to divide the polynomial f(x) by x−2, as shown on the table. What is the value of f(2)? −14 −11

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Step-by-step explanation:

The answer to the first one sould be -11

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2x^3 + 4x^2 + x^2 - x - 6

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3 years ago

Arvin has $10000 to invest. He invests part in a term deposit paying 5%/year, and the remainder in Canada savings bonds paying 3

Delicious77 [7]

Answer:

$4,562.5

Step-by-step explanation:

The amount Arvin has to invest, P = $10,000

The interest paid on the investment in the term deposit = 5%/year

The interest paid om the investment in Canada savings bonds = 3.4%/year

The amount Arvin earned at the of the year as simple interest, A = $413

Let, x, represent the amount Arvin invested in the term deposit and let, y, represent the amount he invested in Canada savings bonds, we can get the following system of equations

x + y = 10,000...(1)

0.05·x + 0.034·y = 413...(2)

Making y the subject of equation (1) and substituting the value in equation (2), we get;

From equation (1), we get, y = 10,000 - x

Plugging the above value of y in equation (2) gives;

0.05·x + 0.034 × (10,000 - x) = 413

∴ 0.05·x - 0.034·x + 340 = 413

x = (413 - 340)/(0.05 - 0.034) = 4,562.5

Therefore, the amount Arvin invested in the term deposit at 5%, x = $4,562.5

(y = 10,000 - x

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The amount Arvin invested in Canada savings bonds, y = $5,437.5.)

8 0

3 years ago

I’m just really sleep deprived sorry 25/2 x 85/5

Katena32 [7]

Your answer is 212.5

4 0

4 years ago

Read 2 more answers