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3 years ago

Find the value of 7 + 32 (-5 + 1) ÷ 2.

Mathematics

2 answers:

vampirchik [111]3 years ago

8 0

The answer is -57
7+32(-4)/2
7+-128/2
7+-64
-57

Sidana [21]3 years ago

6 0

Hope this helps........

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Solve the equation 3(x-8)=15 x=___

KengaRu [80]

X = 13
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3 years ago

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What is the length of the line?

elixir [45]

If you count the squares or units I got 12.

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3 years ago

Use the method of "undetermined coefficients" to find a particular solution of the differential equation. (The solution found ma

Naddika [18.5K]

Answer:

The particular solution of the differential equation

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

Step-by-step explanation:

Given differential equation y''(x) − 10y'(x) + 61y(x) = −3796 cos(5x) + 185e6x

The differential operator form $(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

Rules for finding particular integral in some special cases:-

let f(D)y = $e^{ax}$ then

the particular integral $\frac{1}{f(D)} (e^{ax} ) = \frac{1}{f(a)} (e^{ax} ) if f(a)$ ≠ 0

let f(D)y = cos (ax ) then

the particular integral $\frac{1}{f(D)} (cosax ) = \frac{1}{f(D^2)} (cosax ) =\frac{cosax}{f(-a^2)}$ f(-a^2) ≠ 0

Given problem

$(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

Particular integral:-

$P.I = \frac{1}{f(D)}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + \frac{1}{D^2-10D+61}185e^{6x})$

P.I = $I_{1} +I_{2}$

we will apply above two conditions, we get

$I_{1}$ =

$\frac{1}{D^2-10D+61}( −3796 cos(5x) = \frac{1}{(-25)-10D+61}( −3796 cos(5x) ( since D^2 = - 5^2)$ $= \frac{1}{(36-10D}( −3796 cos(5x) \\= \frac{1}{(36-10D}X\frac{36+10D}{36+10D} ( −3796 cos(5x)$

on simplification we get

= $\frac{1}{(36^2-(10D)^2}36+10D( −3796 cos(5x)$

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{1296-100(-25)}$

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$

$I_{2}$ =

$\frac{1}{D^2-10D+61}185e^{6x}) = \frac{1}{6^2-10(6)+61}185e^{6x})$

$\frac{1}{37}185e^{6x})$

Now particular solution

P.I = $I_{1} +I_{2}$

P.I = $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

8 0

3 years ago

A line contains the points (–4, 5) and (3, –9). Write the equation of the line using slope-intercept form.

Galina-37 [17]

(-4,5)(3,-9)
slope = (-9 - 5) / (3 - (-4) = -14 / (3 + 4) = -14/7 = -2

y = mx + b
slope(m) = -2
use either of ur points...(-4,5)...x = -4 and y = 5
now we sub and find b, the y int
5 = -2(-4) + b
5 = 8 + b
5 - 8 = b
-3 = b

so ur equation is : y = -2x + (-3) which can be written as : y = -2x - 3

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4 years ago

How do I find the total perimeter of a odd shape

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The area of the irregular shape is the area of the two rectangles added together. Use the measure calculate feature of Geometer's Sketchpad to add the areas. The perimeter of the irregular shape is equal to the sum of the six segment around the outside of the figure.

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