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3 years ago

Simplify the expression. 18+12x.

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

12x+18

Step-by-step explanation:

That is allready completely simplified.

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I need help please.

jeka57 [31]

We are trying to represent the change in position of a bird flying down 7 ft to the ground.

Often, for the y axis- up is positive and down is negative.

Change in position is displacement- how far it was from the starting point

( different from distance which is how far is traveled

ex. doubling back would have distance they traveled some distance while the displacement is 0 because they are back to where they started).

The bird is going down 7 ft from where it originally was, which can be represented by

Bird's displacement = -7 ft

5 0

3 years ago

Help on word problems plz!! :)

-Dominant- [34]

I can help you with 11 so its 588 because I know that 600 divide by 12 equals 50 so they said they want less then 600 so I tried 49 times 12 equals 588

4 0

3 years ago

The soccer team voted on what they wanted to eat. There are 20 members on the team. Six members voted for pizza, 10 voted for ch

sleet_krkn [62]

Hot dogs = 20 -10-6 = 4

Ratio = hotDogs/Chicken = 4/10 = 2/5

4 0

3 years ago

Read 2 more answers

1)Jamal has 24 inches of yarn. How many feet of yarn does he have?2) Ricardo has 1/2 of a foot of yarn. How many inches does he

solniwko [45]

Answer:

Jamal has 2.5 feet of yarn

Step-by-step explanation:

3 0

2 years ago

Suppose a sample of size 400 yields pˆ = .5. You'd like to construct a confidence interval with a margin of error only half as g

lutik1710 [3]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.0245}{1.96})^2}=1600$

c. 1600

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to solve this problem we need to assume a confidence level. Let's assume that is 95%

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: