I need help -7y^2-2y^2+y^3-3y-2y+5y^3-2y
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Answer:
Step-by-step explanation:
Hello!
You have the information for two variables
X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.
n₁= 120 consumer purchases
x₁= 48 cash purchases
p'₁= 48/120= 0.4
X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.
n₂= 55 consumer purchases
x₂= 24 cash purchases
p'₂= 24/55= 0.4364
You need to construct a 90% CI for the difference of proportions p₁-p₂
Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:
[(p'₁-p'₂) ± *
]
[(0.4-0.4364)±1.648 * ]
[-0.1689;0.0961]
The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.
I hope this helps!
y -
y1 = m (x - x1)
where m is the slope and (x1 , y1) is the point given
we have <span>(-5,-3) and (6,1)
so: m = (1- -3) / (6- -5) = (1+3)/(6+5) = 4/11
and the equation of the line is:
</span>y - y1 = m (x - x1)
y-1 = 4/11 (x-6)
simplify:
y = 4/11 x - 24/11 +1
I hope that helps!