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lawyer [7]
3 years ago
6

I need help -7y^2-2y^2+y^3-3y-2y+5y^3-2y

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

6

3

−

9

2

−

7

Step-by-step explanation:

Combine like terms

−

7

2

−

2

2

+

3

−

3

−

2

+

5

3

−

2

{\color{#c92786}{-7y^{2}}}{\color{#c92786}{-2y^{2}}}+y^{3}-3y-2y+5y^{3}-2y

−7y2−2y2+y3−3y−2y+5y3−2y

−

9

2

+

3

−

3

−

2

+

5

3

−

2

Combine like terms

−

9

2

+

3

−

3

−

2

+

5

3

−

2

-9y^{2}+y^{3}{\color{#c92786}{-3y}}{\color{#c92786}{-2y}}+5y^{3}{\color{#c92786}{-2y}}

−9y2+y3−3y−2y+5y3−2y

−

9

2

+

3

−

7

+

5

3

Combine like terms

−

9

2

+

3

−

7

+

5

3

-9y^{2}+{\color{#c92786}{y^{3}}}-7y+{\color{#c92786}{5y^{3}}}

−9y2+y3−7y+5y3

−

9

2

+

6

3

−

7

Rearrange terms

−

9

2

+

6

3

−

7

{\color{#c92786}{-9y^{2}+6y^{3}-7y}}

−9y2+6y3−7y

6

3

−

9

2

−

7

Solution

6

3

−

9

2

−

7

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Step-by-step explanation:

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7 0
3 years ago
(-6,8); perpendicular to y = -3/2x -1
UNO [17]

Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

- 1 \div ( -  \frac{3}{2} ) \\  =  - 1( -  \frac{2}{3} )  \\  =  \frac{2}{3}

Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

7 0
3 years ago
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