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mamaluj [8]
3 years ago
7

(3^5 x 3^7) = 3^35 is this true

Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer:

False

Step-by-step explanation:

you have to solve the problems inside the parentheses first so you would have to multiply everything inside so no ur wrong

Real answer is: 531,441

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The table shows locations on a map.
Nina [5.8K]

Answer:

The table shows locations on a map.

<u>Place</u>

  1. park
  2. farmers market
  3. post office
  4. bus stop

<u>Location</u>

  1. (-2,2)
  2. (-2,3)
  3. (2, 2)
  4. (6,-3)

Which places on the map are 4 units apart?

O the park and the farmer's market

O the farmers market and the bus stop

<em><u>✓</u></em> <em><u>the post office and the park</u></em>

O the post office and the bus stop

Step-by-step explanation:

Distance :---

→ \sqrt{ {(2 - ( -2 ))}^{2}  + {(2 - 2)}^{2}  } \\   = \sqrt{ {4}^{2} +  {0}^{2}  }  =  \sqrt{ {4}^{2} }  =  \boxed{4 \: units}

5 0
3 years ago
What is the solution to the inequality 14y−14≥14?
makkiz [27]
14y > 0 is the answer
6 0
2 years ago
Read 2 more answers
22. The height of a triangle is 4 centimeters less than the base. Write a function that
torisob [31]

The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

let the base of the triangle be x

Height of the triangle = x - 4

Area of triangle = 1/2 × base × height

Area = 1/2 × x × (x-4)

Area = 1/2 (x² - 4x)

Area = 1/2 x² - 2 x

We can also write it as a function:

y = 1/2 x² - 2 x

Domain = (3 , ∞)

Range = [0, ∞)

Since 3 is not included in the domain, base of the triangle cannot be 3 cm.

Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

Learn more about function here:

brainly.com/question/2456547

#SPJ9

6 0
1 year ago
At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not
Nikitich [7]
If f(x, y, z) = c represent a family of surfaces for different values of the constant c. The gradient of the function f defined as \nabla f is a vector normal to the surface f(x, y, z) = c.

Given <span>the paraboloid

y = x^2 + z^2.

We can rewrite it as a scalar value function f as follows:

f(x,y,z)=x^2-y+z^2=0

The normal to the </span><span>paraboloid at any point is given by:

\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\  \\ =2xi-j+2zk

Also, the normal to the given plane 3x + 2y + 7z = 2 is given by:

3i+2j+7k

Equating the two normal vectors, we have:
</span>
2x=3\Rightarrow x= \frac{3}{2}  \\  \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}

Since, -1 = 2 is not possible, therefore there exist no such point <span>on the paraboloid y = x^2 + z^2 such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>.
4 0
3 years ago
A square is divided into smaller squares and portions are shaded. What is the area of the shaded portion
prohojiy [21]
We can’t see
There is nothing attached
3 0
2 years ago
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