Answer: 1,200
Step-by-step explanation:
1,200 x .125 = 150
Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Answer:
$2.64
Step-by-step explanation:
Selling them at 5 cents each ($0.05), he could sell 1 dozen buttons for
12 * $0.05 = $0.60
As he bought them at $0.38 per dozen, the profit per dozen would be
$0.60 - $0.38 = $0.22
As 12 dozen is 1 gross, the profit per gross would be
12 * $0.22 = $2.64
Answer:
(-4) (0)
Step-by-step explanation:
Answer:
Step-by-step explanation:
t = tutoring and g = grocery store
t + g = 15......t = 15 - g
15t + 9g = 159
15(15 - g) + 9g = 159
225 - 15g + 9g = 159
-15g + 9g = 159 - 225
-6g = - 66
g = -66/-6
g = 11 <===== 11 hrs worked at the grocery store
t + g = 15
t + 11 = 15
t = 15 - 11
t = 4.....4 hrs tutoring