Since the equation is parallel to y=2x-4 that means they have the same slope. Now that you have the slope and fortunately a point, you can solve this by using point slope formula
Which is what I did on the attached picture and just rearrange it after solving to Ax+By=C/2x-y=6
74-17= 57 because if you subtract 10 from 74, it would be 64, then you need to subtract 7 from 64, which gives you 57.
9+7=16 because 10+7 would be 17, but since 9 is one less than 10, you need to subtract one from 17, which gives you 16.
17+(-30)=(-13) because adding 17 to -30 only brings up -30 to -13, and -30<-13.
-41+24=-17. Same reason as question 3, only different numbers.
-36+(-7)=-43 because adding two negatives together is like subtracting two positives from each other.
14+64=78 because adding 10 to 64 is 74 and 74+4=78.
-53-42=-95 because when you subtract a positive from a negative, it decreases the number even more.
-17-(-62)=45 because -62 is less than -17 and it is being subtracted from -17 so the answer becomes positive.
Hope this helps :)
Answer:
ok.
what benchmark 1 1/8 is closet to (ps benchmarks on the side) and do the same for 2 2/5 . and the benchmarks that you found subtract them.
lol sorry though I don't know sorry
Step-by-step explanation:
Hello,
26.
period=4
max=3
min=-3
27:
p=8
max=5
min=0
28:
p=8
max= 4 (twice)
min=-4 (twice)
Answer:
6√3 ±3 ≈ {7.392, 13.392}
Step-by-step explanation:
The length of AB is the long side of a right triangle with hypotenuse CD and short side (AC -BD). The desired radius values will be half the length of EF, with AE added or subtracted.
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<h3>length of AB</h3>
Radii AC and BD are perpendicular to the points of tangency at A and B. They differ in length by AC -BD = 12 -9 = 3 units.
A right triangle can be drawn as in the attached figure, where it is shaded and labeled with vertices A, B, C. Its long leg (AB in the attachment) is the long leg of the right triangle with hypotenuse 21 and short leg 3. The length of that leg is found from the Pythagorean theorem to be ...
AB = √(21² -3²) = √432 = 12√3
<h3>tangent circle radii</h3>
This is the same as the distance EF. Half this length, 6√3, is the distance from the midpoint of EF to E or F. The radii of the tangent circles to circles E and F will be (EF/2 ±3). Those values are ...
6√3 ±3 ≈ {7.392, 13.392}
