3 years ago

A set of equations is given below:

Mathematics

1 answer:

miv72 [106K]3 years ago

5 0

<span>Equation F can be written as 2d + 1 = 3d + 7.</span>

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Does the following relationship represent a function?

Sloan [31]

No the relationship is not a function

7 0

2 years ago

Find all real zeros of the function y=-6x-5, b. –6 d. –6, –5 Please select the best answer from the choices provided A B C D

Lelechka [254]

Answer:

$x=-\frac{5}{6}$

Step-by-step explanation:

Equation given: y=-6x-5.

In order to find zeros of an equation, substitute y=0 in the given equation.

0=-6x-5

-6x-5=0

-6x=5

$x=\frac{5}{-6}\\x=-\frac{5}{6}$

Therefore, $x=-\frac{5}{6}$ is zero for our given equation

4 0

3 years ago

The function f(x)=log4x is dilated to become g(x)=f(13x).<br> What is the effect on f(x)?

castortr0y [4]

Answer:

f(x) is compressed horizontally

Step-by-step explanation:

Given

$f(x) = \log(4x)$

$g(x) = f(13x)$

Required

The effect on f(x)

$g(x) = f(13x)$ implies that f(x) is horizontally compressed by 13.

So, we have:

$f(13) = \log(4 * 13x)$

$f(13) = \log(52x)$

So:

$g(13) = \log(52x)$

5 0

3 years ago

What is the length of the conjugate axis?

Lana71 [14]

ANSWER

The length of the conjugate axis is 6 units.

EXPLANATION

The given hyperbola has equation:

$\frac{(x - 1)^{2} }{25} - \frac{ {(y + 3)}^{2} }{9} = 1$

We can rewrite this equation in the form:

$\frac{(x - 1)^{2} }{ {5}^{2} } - \frac{ {(y + 3)}^{2} }{ {3}^{2} } = 1$

We compare this equation to:

$\frac{(x - h)^{2} }{ {a}^{2} } - \frac{ {(y - k)}^{2} }{ {b}^{2} } = 1$

This implies that;

$a = 5$

and

$b = 3$

The length of the conjugate axis of a hyperbola is

$= 2b$

Substitute b=3 to obtain;

$= 2 \times 3$

$= 6$

5 0

3 years ago

Read 2 more answers

Data scored 42 points in 3 games. How many points would you expect him to make in an 11 game season?

dimulka [17.4K]

Answer:

He would score 154 points because he averages 14 points per game and 11 times 14 is 154

4 0

3 years ago