4 x 10^-7 (7 x 10^-9) (1 x 10^4) (2 x 10^4)
Apply the Pyth. Theorem:
c^2 = 3^2 + 7^2, or c^2 = 9 + 49 = 58. Thus, c = sqrt(58).
Answer is <span>B.
Quadrant II </span>
3x+15= 5x
8y-72= 9y
9a+18= 2a
3b-27= 9b
5c+40= 8c
6c+18= 3c
8c-8= c/1c
5x-10= 2x
2b-16= 8b
7c-35= 5c
