The solution can be anything bigger than 13/6.
For example: 3, 4, 5, 6...ect
The volume of a cone is 84.78 cm
<u>Step-by-step explanation</u>:
<u>Given</u>:
radius = 3 cm and
height = 9 cm
<u>To Find</u>:
The Volume of a Cone
<u>Formula</u>:
The Formula for the volume of a cone is
V=πr2 *h/3
<u>Solution</u>:
V=πr2 *h/3
π value is 3.14
V= 3.14*(3)^2*9/3
V=3.14*9*3
V= 84.78 cm
Therefore the volume is 84.78 cm.
Answer:
1/27 is the answer
Step-by-step explanation:
It is 1/(3^3) which is 1/27
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
The constant of variation for the given quadratic equation is, 30
Step-by-step explanation:
One of the form of a quadratic equation is written as:
....[1]
where k is the coefficient and for this case the constant of variation.
In order to obtain the answer for the given equation, we write the given equation to the form above.
or
or
Comparing this equation with equation [1], to get the value of k;
k=30.
therefore, the constant of variation is, 30.
