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3 years ago

Activity : Find the factors of the following polynomials.

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

8 0

Step-by-step explanation:

1) x^2-5x+x-5

=x(x-5)+1 (x-5)

=(x+1)(x-5)

3) a^2-25

= a^2-(5)^2

= (a+5)(a-5)

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I think I need to find x

ozzi

Answer:

-6

Step-by-step explanation:

the x value is just plugging that number in for x so

-3x-8=10 (add 8 to both sides) so

-3x=18 (divide by -3 on both sides) so

x=-6

7 0

3 years ago

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Find the time required for an investment of 5000 dollars to grow to 9000 dollars at an interest rate of 7.5

umka2103 [35]

Answer:

i think its 3.5 years

Step-by-step explanation:

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2 years ago

What is the next step to solve this equation?<br> 3x - 5 = 7

Ronch [10]

Answer:

Find the value of x the value is x=4

3x4=12

12-5=7

Step-by-step explanation:

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3 years ago

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Estimate then find the difference or sum <br><br> 86+17

kumpel [21]

Estimation for addition: 86 rounds up to 90 and 17 rounds up to 20 so:
90 + 20 = 110
Estimation for subtraction is the same thing but with subtraction
90 - 20 = 70

Now for the exact answers:
86 + 17 = 103
86 - 17 = 69

Your answers are 110, 70, 103, and 69.

8 0

3 years ago

]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf

Anna35 [415]

Answer:

$\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

Step-by-step explanation:

Circumference of circle = $\pi \cdot d$

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to $\frac{360^{\circ}}{n^{\circ}}$

So, Number of sectors = $\frac{360^{\circ}}{n^{\circ}}$

The arc length of each sector is the circumference divided by the number of sectors

$\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}$

Diameter d = 2r (r = radius)

$\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$

Option b is true

Hence $\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

7 0

3 years ago