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Rudik [331]
4 years ago
7

the pressure inside a tire is measured as 28.0 pounds/inch. What is the pressure in newtons/centimeter?

Chemistry
1 answer:
Valentin [98]4 years ago
3 0

Answer:

49.028 N/cm

Explanation:

The pressure expressed as 28.0 pounds/inch can be converted to newtons/centimeter as follow

1 pounds/inch = 1.751 N/cm

Therefore, 28 pounds/inch = 28 x 1.751 = 49.028 N/cm

Therefore, 28 pounds/inch is equivalent to 49.028 N/cm

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Earth is removed from the top to reveal the coal. Which type of coal mine does this describe? undersea subterranean drill strip
Misha Larkins [42]

Answer:

Strip

Explanation:

Strip mining removes Earth in long strips from the top to reveal the coal. This earth to be removed is known as 'overburden'. The overburden from the first strip is referred to as out-of-pit dumping. Strip mining is a part of surface mining.

Strip mining destroys forests, landscapes, forests and wildlife habitats as trees and plants are removed from the mining area.

Therefore,

this describes the Strip coal mine.

3 0
3 years ago
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A fruit juice has a very sour taste. What does this most likely indicate?
gavmur [86]

Explanation:

its hard its either B or C i dont wanna be wrong;-;

6 0
3 years ago
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Why would a C-O bond have only provide 358 kJ/mol each while C=O provides 799 kJ/mol? Explain in detail.
Alina [70]

Consider the amount of energy needed to brake the bonds.

In c=o there are both a pi-bond and a sigma bond. Therefore it requires a higher energy to brake it. When considering the c-o bond there is only a single sigma bond is needed to be broken. Therefore braking is easier.

When something is easily broken they are having a weak attraction. When they harder to break they are having a stronger attraction.

Here weak attraction is having a lower energy while stronger attraction has higher energy.

Therefore c=o provides a high energy than c-o

7 0
3 years ago
In your own words right a definition of earth core
Rasek [7]
The Earth's core is the part of Earth in the middle of our planet. It has a solid inner coreand a liquid outer core.
7 0
3 years ago
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How do I solve for V1 in this equation ​
arlik [135]

Answer:

<h2>V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}</h2>

Explanation:

\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

<u>First of all cross multiply</u>

That's

P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}

<u>Next divide both sides by </u>P_{1}T_{2}<u>  in order to isolate </u>V_{1}

We have

\frac{P_{1}V_{1}T_{2}}{P_{1}T_{2}} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

We have the final answer as

V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

Hope this helps you

3 0
4 years ago
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