All categories

3 years ago

Simplify -6^2 ÷ 12 - 2(-7). A. -17 B. 35 C. 11 D. -35

Mathematics

1 answer:

vladimir2022 [97]3 years ago

8 0

$-6^2\:\div \:12\:-\:2\left(-7\right)\:$

$-36/12-2(-7)$

$-3-2(-7)$

$-3-(-14)$

$=11$

The answer is C.

Hope this helps!

Thanks!

-Charlie

You might be interested in

Estimate the product. Solve using an area model and the standard algorithm. Remember to express your products in standard form.

snow_tiger [21]

Answer:

Step-by-step explanation:

Using the area model and standard algorithm, we have:

332 (tenths)

× 21

332

664

6972 tenths = 697.2

30 + 3 tenths

1 300 32 332

20 600 64 664

33.2 × 21 = 30 × 1 = 30

8 0

2 years ago

HELP FAST select the correct answer

Aleks04 [339]

Answer:

Step-by-step explanation:

8 0

2 years ago

What is the solution of the equation 4p/6+27

anyanavicka [17]

The answer is 36 I'm pretty sure

7 0

3 years ago

what �is the equation of a line that is perpendicular to the line y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr

gladu [14]

Answer:

$y=\frac{1}{25}x-\frac{31}{25}$

Step-by-step explanation:

$y=-25x-5$

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

$-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}$

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

$(y-y_0)=m(x-x_0)$

$y-1=\frac{1}{25} (x-6)$

Rearrange for y and collect terms.

$y=\frac{1}{25}x-\frac{6}{25}-1\\\\y=\frac{1}{25}x-\frac{31}{25}$

8 0

3 years ago

Find the missing exponent: 2^3 times 2^? = 2^10

LenKa [72]

Answer:

2^7

Step-by-step explanation:

3+7=10

6 0

3 years ago