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2 years ago

Solve equation 7x+5y= 15 for y

Mathematics

1 answer:

alina1380 [7]2 years ago

6 0

Answer: 3 - 7x/5

Explanation: move all terms that don’t contain y to the right side and solve.

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Differences between 7 1/8 - 1 7/8

Mrrafil [7]

(7-1/8) - (1-7/8) = 57/8 -15/8 = 21/4

8 0

3 years ago

Read 2 more answers

Factor. to 4m6 – 16p10

Nonamiya [84]

Answer:

4 ( m⁶ - 4p¹⁰ )

Step-by-step explanation:

4m⁶ = 4 * m⁶

16p¹⁰= 4 * 4 * p¹⁰

Common factor = 4

4m⁶ - 16p¹⁰ = 4 ( m⁶ - 4p¹⁰ )

3 0

2 years ago

Kayla get paid $15 to rake the lawn. Kayla get paid 3 times as much to rake the lawn as she does to mow the lawn. How much does

Xelga [282]

Answer :

15$ x 3 = 45 

Step-by-step explanation:

You just have to multiply the amount that kayla gets payed (15$) to the number of times that she mows the lawn ( 3 times ).

Then you do the eqaution which is :

15$ x 3 

And that give you your answer which is:

45 :)

4 0

3 years ago

A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a

BigorU [14]

Answer:

$R'(20) = 2000$

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

$q=f(p)$

Total revenue earned =

$R(p)=pf(p)$

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

$R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)$

Putting the values, we get,

$R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000$

7 0

3 years ago

For the data set { -4 , 8 , 4 , 0 , 7 , -2 , -5 , 6 }, the range is

statuscvo [17]

The interquartile range is 9.5.

Hope this helps!!!!!!

Please give me brainliest!!!!!!!!

3 0

3 years ago