Anyone know what -10 + 9 is?

4,139 divided by 14 equals what?

Anon25 [30]

Answer:

that would be 57,946

3 0

3 years ago

Read 2 more answers

A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma

Gnoma [55]

Answer:

The value is $C \approx \$76$

Step-by-step explanation:

From the question we are told that

The area of the rectangular pen is $A = 24 \ yard^2$

The cost of material used to make one side is $z = \$ 6$

The cost of material used to make the other sides is $r = \$ 3$

Now , the fence to be build around the rectangular pen has four sides, the first opposite sides are equal, let assume each of the to be x yard and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

$C = zx + r (x + 2y )$

=> $C = 6x + 3(x + 2y)$

=> $C = 9x + 6y$

Now the area of the fence is mathematically represented as

$A = x* y = 24$

=> $y = \frac{24}{x}$

=> $C = 9x + 6[\frac{24}{x} ]$

=> $C = 9x + [\frac{144}{x} ]$

Now differentiating

$C' = 9 + 144* (-2) x^{-2}$

$C' = 9 - 288x^{-2}$

At minimum $C' = 0$

So

$9 - 288x^{-2} = 0$

$x^{-2} = 0.03125$

$x = \sqrt{\frac{1}{0.03125} }$

$x = 5.66$

Now substituting for x in the equation above to obtain minimum cost

$C = 9(5.66) + [\frac{144}{5.66} ]$

$C \approx \$76$

8 0

3 years ago

find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)

Paraphin [41]

This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c

c = 1

If c =1,

6 = a + 1
a = 5

This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?

5 0

3 years ago

Please help me am I. troubles

Zanzabum

Answer:

$\frac{ {x}^{2} }{y(x - y)} + \frac{ {y}^{2} }{ - x(x - y)}$

$\frac{ {x}^{2} }{y(x - y)} - \frac{ {y}^{2} }{x(x - y)}$

$\frac{ {x}^{2} \times x - {y}^{2} \times y}{xy(x -y)}$

$\frac{(x - y)( {x}^{2} + xy + {y}^{2}) }{xy(x - y)}$

$\frac{ {x}^{2} + xy + {y}^{2} }{xy}$

7 0

2 years ago

In the United States, among a representative group of 6,006 white men and 1,126 black men, ages 70-79 at diagnosis with stage IV

Ivenika [448]

Answer:

White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.

Step-by-step explanation:

The exposure is race and the outcome is survival.

Race Alive Dead T

W 2337 3669 6006

B 344 782 1126

Relative Risk - 1.27

White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.

7 0

2 years ago