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sergiy2304 [10]
3 years ago
9

In which of the following stores would you pay the least amount for an item that is priced $360? Store A: Sale of 10% off and a

successive discount of 10% off. Store B: Sale of 15% with no additional discount. Store C: Sale of $35 off and a successive discount of 10% off.
Mathematics
2 answers:
Gnoma [55]3 years ago
6 0

Answer:

option b

Step-by-step explanation:


Airida [17]3 years ago
5 0
Given:
Price : 360

Store A: Sale of 10% off and a successive discount of 10% off.
360 * (100-10)% = 360 * 90% = 324
324 * (100-10)% = 324 * 90% = 291.60

Store B: Sale of 15% with no additional discount
360 * (100-15)% = 360 * 85% = 306

Store C: Sale of $35 off and a successive discount of 10% off
360 - 35 = 325
325 * (100-10)% = 325 * 90% = 292.50

Store A has the least amount to pay for an item at price of 291.60
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Answer:

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x+4

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What is the volume of the cylinder shown below? A. 12157 units B. 3617 units C. 647 units D. 152 T units
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3 years ago
A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red
mamaluj [8]

Let red marbles = X.

The probability is 1 out of 5, written as 1/5

1/5 in terms of red marbles is equal to the number of red marbles divided by 5x, where 5x is the total number of marbles.

1/5 = x/5x 

Now you have 5x total marbles, x red and 4x blue. 

Add 5 more red and the new probability is: 

(x+5)/(5x+5) = 1/3 

Simplify:

3x+15 = 5x+5 

Now solve for x:

Subtract 3x from both sides:

15 = 2x +5

Subtract 5 from each side:

2x = 10 

Divide both sides by 2:

x = 10/2

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5 0
3 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
1 year ago
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