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Lunna [17]
3 years ago
7

Give an example of an odd function and explain algebraically why it is odd.

Mathematics
1 answer:
NARA [144]3 years ago
4 0
F(x) = x^3
f(-x) = (-x)^3 = -x^3
but if u factor out the negative then
f(-x) = -(x)^3
therefore it is an odd function because f(-x) = -f(x)
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Naya [18.7K]
Hope this helped! the answer is 2^7

7 0
3 years ago
Find the equation of the line in slope-intercept form. m=− 4 7 through (14, 3)
fomenos
I think your answer is y=-4/7x+5
7 0
3 years ago
Solve this x²+8/10 -x = 10/2
AysviL [449]
x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\



x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
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7 0
3 years ago
Find the area of the shape shown below.
vlabodo [156]

Answer:

6cm^{2} (assuming the units is in centimetres)

Step-by-step explanation:

Hi, hope this helps!

Method 1:

Calculate this shape as a trapezium. This is a trapezium because it has one pair of parallel sides. The way to calculate the area of a trapezium is this:

- Half the sum of the parallel sides

- Multiply the perpendicular height between them

In this case, 4 and 2 are parallel, so we add them together (4 + 2 = 6) then we divide by two (6 ÷ 2 = 3). Then we multiply our answer by the perpendicular length between the two parallel sides (assuming the side on the left is at a right-angle, 3 x 2 = 6).

Method 2:

Calculate this shape as a rectangle + a triangle. If you split the shape so the pointy bit on the right becomes a triangle and the left becomes a square, you can calculate the area without knowing the formula for calculating a trapezium (see above ^).

- Area of the square / rectangle = length x width = 2 x 2 = 4

- Area of the triangle = 1/2 x length x width = 2 x 2 x 1/2 = 4 x 1/2 = 4 ÷ 2 = 2

Then we add the two areas together (4 + 2 = 6).

I hope this helped and I wasn't waffling on :)

Bluey

8 0
3 years ago
Read 2 more answers
What type of line is PQ?
goblinko [34]

Answer:

Option C, angle bisector

Answered by GAUTHMATH

8 0
3 years ago
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