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chubhunter [2.5K]
3 years ago
10

An expression is shown below:

Mathematics
2 answers:
olganol [36]3 years ago
7 0

Answer:

An expression is shown below:

10n³− 15n² + 20xn² − 30xn

Part A: Rewrite the expression so the GCF is factored completely. (4 points)

10n³− 15n² + 20xn² − 30xn

2*5*n*n*n-5*3*n*n+2*5*2*x*n*n-2*5*3*x*n

<u>Greatest</u><u> </u><u>common</u><u> </u><u>factor</u><u>=</u><u>5</u><u>*</u><u>n</u><u>=</u><u>5</u><u>n</u>

Part B: Rewrite the expression completely factored. Show the steps of your work.

Solution given;

10n³− 15n² + 20xn² − 30xn

5n(2n²-3n+4xn-6x)

5n(2n²+4xn-3n-6x)

5n(2n(n+2x)-3(n+2x))

<u>5n(n+2x)(2n-3</u>)

lilavasa [31]3 years ago
4 0

Answer:

5n(2n-3)(n+2x)

Step-by-step explanation:

<u>Step 1:   Rewrite the expression so the GCF is factored completely</u>

<u />10n^{3} - 15n^{2} + 20xn^{2} - 30xn

The GCF is 5n so factor it out

5n(2n^{2} - 3n + 4xn - 6x)

<u>Step 2:  Rewrite the expression completely factored</u>

<u />5n(2n^{2} - 3n + 4xn - 6x)

5n(2n(n+2x)-3(n+2x))

5n(2n-3)(n+2x)

Answer:  5n(2n-3)(n+2x)

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