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3 years ago

An expression is shown below:

Mathematics

2 answers:

olganol [36]3 years ago

7 0

Answer:

An expression is shown below:

10n³− 15n² + 20xn² − 30xn

Part A: Rewrite the expression so the GCF is factored completely. (4 points)

10n³− 15n² + 20xn² − 30xn

2*5*n*n*n-5*3*n*n+2*5*2*x*n*n-2*5*3*x*n

Greatest common factor=5*n=5n

Part B: Rewrite the expression completely factored. Show the steps of your work.

Solution given;

10n³− 15n² + 20xn² − 30xn

5n(2n²-3n+4xn-6x)

5n(2n²+4xn-3n-6x)

5n(2n(n+2x)-3(n+2x))

5n(n+2x)(2n-3)

lilavasa [31]3 years ago

4 0

Answer:

$5n(2n-3)(n+2x)$

Step-by-step explanation:

Step 1: Rewrite the expression so the GCF is factored completely

$10n^{3} - 15n^{2} + 20xn^{2} - 30xn$

The GCF is 5n so factor it out

$5n(2n^{2} - 3n + 4xn - 6x)$

Step 2: Rewrite the expression completely factored

$5n(2n^{2} - 3n + 4xn - 6x)$

$5n(2n(n+2x)-3(n+2x))$

$5n(2n-3)(n+2x)$

Answer: $5n(2n-3)(n+2x)$

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What is the unit rate for 297 words in 5.5 minutes

Stolb23 [73]

297:5.5

divide 5.5 by both sides which

5.5 divided by 5.5 is 1 and 297 divided by 5.5 is 54

1:54

the unit rate:

54 minutes per word or 54/1

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3 years ago

Read 2 more answers

Somebody please assist me in answering this math question.

Sphinxa [80]

Firstly look at the options carefully and we will get to know that two answer options are incorrect because 2 of them are representing AT MOST SIGN which we don't need. So in that way Options B and D are eliminated.

So Now we are left with 2 options A and C. Lets figure it out.
We know that Carlos has 5 complete set with 4 individual figures and josh has 3 complete sets with 14 individual figures.
So lets write in the numerical language:-
let us assume that complete sets are X.
ATQ,
5x + 4 ≥ 3x + 14
subtracting 3x from both sides.
5x -3x + 4 ≥ 14
2x + 4 ≥ 14
subtracting 4 from both sides
2x ≥ 14 - 4
2x ≥ 10
dividing both sides by 2
x ≥ 5 Answer
So correct answer option is C

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3 years ago

The times for Erin’s five laps around the track were 56.6 seconds, 57.9 seconds, 57.5 seconds, 65.3 seconds, and 65.7 seconds. U

Evgesh-ka [11]

Answer:

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3 years ago

a boat travels upstream on the allegheny river for 2 hours. the return trip only takes 1.7 hours because the boat travels 2.5 mi

Gre4nikov [31]

To solve this we are going to use the speed equation: $S= \frac{d}{t}$
where
$S$ is speed
$d$ is distance
$t$ time

We know from our problem that the upstream trip takes 2 hours, so $t_{u}=2$ . We also know that the downstream trip takes 1.7 hours, so $t_{d}=1.7$ . Notice that the distance of both trips is the same, so we are going to use $d$ to represent that distance.
Now, lets use our equation to relate the quantities:

For the upstream trip:
$S_{u}= \frac{d}{t_{u} }$
$S_{u}= \frac{d}{2}$ equation (1)

For the downstream trip:
$S_{d}= \frac{d}{t_{d} }$
$S_{d}= \frac{d}{1.7}$ equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
$S_{u}=S_{d}-2.5$ equation (3)

Replacing (3) in (1):
$S_{u}= \frac{d}{2}$
$S_{d}-2.5= \frac{d}{2}$ equation (4)

Solving for $d$ in equation (2):
$S_{d}= \frac{d}{1.7}$
$d=1.7S_{d}$ equation (5)

Replacing (5) in (4):
$S_{d}-2.5= \frac{d}{2}$
$S_{d}-2.5= \frac{1.7S_{d}}{2}$
$2(S_{d}-2.5)=1.7S_{d}$
$2S_{d}-5=1.7S_{d}$
$0.3S_{d}=5$
$S__{d}= \frac{5}{0.3}$
$S_{d}= \frac{50}{3}$ equation (6)

Replacing (6) in (5)
$d=1.7S_{d}$
$d=1.7( \frac{50}{3} )$
$d= \frac{85}{3}$ miles

We can conclude that the boat travel $\frac{85}{3}$ , which is approximately 28.3 miles, in one way.

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erik [133]

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