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tankabanditka [31]
3 years ago
8

Which set of ordered pairs does NOT represent a function? A) (0, 1), (2, 2), (4, 8), (-2, 7), (5, 8) B) (0, 1), (2, 2), (4, 8),

(2, 7), (5, 8), (7, 9) C) (-3, 6), (2, 7), (0, 5), (1, 5), (4, 9), (5, 4) D) (-4, 2), (-3, 2), (-2, 2), (-1, 2), (0, 2), (1, 2) Submit
Mathematics
1 answer:
Viktor [21]3 years ago
8 0
That is B
Because there are duplicate x-values in the ordered pairs,  ( the (2,2) and the (2,7).
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According to the graph......
Fantom [35]
D because 0.4/x= y :)
4 0
2 years ago
What's 1/8+1/4.Make sure your answer fully reduced​
ArbitrLikvidat [17]

Answer:

3/8

Step-by-step explanation:

1/8+1/4=1/8+2/8=3/8

6 0
2 years ago
Read 2 more answers
AC = 16, AB = x + 1, and BC = x + 7. What is the measure of the length of AB? HELP
saveliy_v [14]

Answer:

5

Step-by-step explanation:

AC=AB+BC

so 16=x+1+x+7

which simplifies to 16=2x+8

subtract eight from both sides to get 8=2x

then divide by 2 to get that x=4

AB=x+1, which substitutes into 4+1=5

6 0
3 years ago
Can anyone solve this for me?? I will give brainliest and 5 stars and thanks
Tcecarenko [31]

Answer:

3 cm

Step-by-step explanation:

When we enlarge or shrink an object, we perform a dilation. A dilation preserves the relationship between sides and the exact angle measure. This means the original and the enlargement are proportional and any missing lengths can be found through a proportion.

A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare height over length of the original rectangle to an equal ratio of height to length of the enlargement. Since we do not know height of the enlargement, we will use a variable to write:

\frac{2}{9} =\frac{h}{13.5}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

9h=2(23.5)\\19h=27

I now solve for h by dividing by 9.

\frac{9h}{9} =\frac{27}{9} \\h= 3

The new height is 3 cm.


5 0
3 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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