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Pavlova-9 [17]
3 years ago
9

What is 2[3(4•4+1)]-2•2•2

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0

Answer:

94 is your answer bud. :)

Step-by-step explanation:

frosja888 [35]3 years ago
3 0

2[3(16+1)]-4•2=

=2(3•17)-8=

=2•51-8=

=102-8=

=94

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Find the slope of the line that passes through the
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Answer:

The slope of the line that passes through the points is 0 slope. That is B is the answer.

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Find the product.<br><br> (3x^2+7)(6x^2−4x+5)
Lapatulllka [165]

Answer:

18x^4  − 12x^3 + 57x^2 − 28x + 35

7 0
2 years ago
Read 2 more answers
A mug is 1/8 full. The mug contains 1/6 of a cup of water. Find the capacity of the mug. Write the answer as a fration or mixed
Andre45 [30]

Answer:

The capacity of the mug = 1\frac{1}{3} cups

Step-by-step explanation:

Given - A mug is 1/8 full. The mug contains 1/6 of a cup of water.

To find - Find the capacity of the mug. Write the answer as a fraction or mixed number

Proof -

Let the capacity of water = x

Given that,

A mug is \frac{1}{8} full of water

⇒Total cups of water in the mug = \frac{1}{8} x

Now,

Given that, The mug contains \frac{1}{6} of a cup of water.

∴ we get

\frac{1}{8} x =  \frac{1}{6}

⇒x = \frac{1}{6} × 8

     = \frac{8}{6}

     = \frac{4}{3} = 1\frac{1}{3}

⇒x = 1\frac{1}{3}

∴ we get

The capacity of the mug = 1\frac{1}{3} cups

8 0
3 years ago
Please help I dont understand ​
Lunna [17]
I also think that the answer is B too
3 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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