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zlopas [31]
3 years ago
6

Help please asapppppppp

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

Order of operations is parenthesis, exponents, multiplication, division, addition, subtraction.

since there are no exponents in this problem the next step is -2(2.2)

Simplify the previous step and you get -4.4

final answer is -7.6 - 4.4 = -12

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Svetach [21]

Alrighty Daniel I think I've figured it out for you. A and B are 55° each, and then C is 70°. Hope I've helped!!

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2 years ago
Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv
mestny [16]

Answer:

  • B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

Step-by-step explanation:

<u>Graph of the function:</u>

  • y = -√x + 1

The domain is x ≥ 0, the range y ≤ 1

Correct answer choice is B

  • On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

<em>The graph is attached</em>

7 0
3 years ago
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Expand.<br> If necessary, combine like terms.<br> (x+3)(x – 3) = ?
Kobotan [32]

Step-by-step explanation:

multiply it

x²-3x+3x-9=0

x²-9=0

x²=9

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x=3

5 0
3 years ago
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ANSWER ASAP GIVING BRAINLIEST FIVE STARS AND A HEART I ONLY NEED A FEW SENTENCES!
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2 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

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3 years ago
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