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3 years ago

What are the coordinates of the midpoint of the line segment with endpoints J (-6, 3) and K (4, -2)

Mathematics

2 answers:

GarryVolchara [31]3 years ago

6 0

It’s C. (-1, 0.5). you add the x coordinates and divide by two and then add the y coordinates and divide by two.

Rzqust [24]3 years ago

4 0

C I think it c I asked my teacher and she said it was c

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(10.05 LC)

loris [4]

Answer:

Cos x = $\frac{base}{hypotenuse}=\frac{\sqrt{3} }{2}$

Tan x = $\frac{perpendicular}{base} = \frac{1}{\sqrt{3} }$

Step-by-step explanation:

Sin x = $\frac{perpendicular}{hypotenuse} = \frac{1}{2}$

So, Perp = 1 and hyp = 2

Putting this in Pythagorean theorem to get the base

$c^2 = a^2+b^2$

$a^2 = c^2-b^2$

base ² = 4-1

base² = 3

Taking square root on both sides

Base = $\sqrt{3}$

Now

Cos x = $\frac{base}{hypotenuse}=\frac{\sqrt{3} }{2}$

Tan x = $\frac{perpendicular}{base} = \frac{1}{\sqrt{3} }$

5 0

4 years ago

Which of the following choices is the simple formula for the nth term of the following arithmetic sequence?

kkurt [141]

$\bf 7~~,~~\stackrel{7-4}{3}~~,~~\stackrel{3-4}{-1}~~,~~\stackrel{-1-4}{-5}~~,~~\stackrel{-5-4}{-9}~~,~~...$

so namely, the "common difference" d = -4, and the first term a₁ = 7.

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=-4\\
a_1=7
\end{cases}
\\\\\\
a_n=7+(n-1)(-4)\implies a_n=7+(4-4n)
\\\\\\
a_n=11-4n\implies a_n=-4n+11$

8 0

3 years ago

The map shows a linear section of Highway 35. Today, the Ybarras plan to drive the 360 miles from

KonstantinChe [14]

5 0

3 years ago

One of the zeros of the polynomial function is 3.

Westkost [7]

The equation in this problem is f(x)=x^4−x^3−7x^ 2+x+6.

The complete factored form of this eqaution is F(x)=(x-1)(x-3)(x+1)(x+2)

-I hope this is the answer you are looking for, feel free to post your questions here on brainly in the future.

5 0

4 years ago

There are four solutions for 61. Three of them are: 61 = 72 + 22 + 22 + 22 , 61 = 52 + 42 + 42 + 22 and 61 = 62 + 52 .What are t

laila [671]

61 = 36 + 16 + 9 = 6² + 4² + 3²

6 0

3 years ago