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V125BC [204]
2 years ago
13

Question 5 and 6 I need answers to

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
4 0

Answer:

and also mark me the brainliest for the answer

Step-by-step explanation:

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An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

D4 = 192 + 3.14 * (48 + 15) = 389.82 yd

D5 = 192 + 3.14 * (48 + 20) = 405.52 yd

D6 = 192 + 3.14 * (48 + 25) = 421.22 yd

D7 = 192 + 3.14 * (48 + 30) = 436.92 yd

D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

6 0
3 years ago
What is on the HANNA ORLEANS ALGEBRA 1 (7th for 8th) PLACEMENT TEST GUIDE?
Fed [463]

Answer:

17

Step-by-step explanation:

ifhrFj,iyjgztizzkyraykeLyrgodyyixynj

3 0
3 years ago
1-m<br> ___ =2/3 HELP PLEASE<br> 1+m
marusya05 [52]

Domain:\\\\1+m\neq0\to m\neq-1\\\\\dfrac{1-m}{1+m}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\3(1-m)=2(1+m)\qquad\text{use distributive property}\\\\(3)(1)+(3)(-m)=(2)(1)+(2)(m)\\\\3-3m=2+2m\qquad\text{subtract 3 from both sides}\\\\-3m=-1+2m\qquad\text{subtract 2m from both sides}\\\\-5m=-1\qquad\text{divide both sides by (-5)}\\\\m=\dfrac{1}{5}\neq-1\\\\Answer:\ \boxed{m=\dfrac{1}{5}}

7 0
3 years ago
Is anyone good at geometry???
zhenek [66]
Hey there Smarty!

This would be considered to be a (acute angel) which in this case, we would have to make sure that this whole triangle would equal less than 270 because each angle would be less than 90°

If we add/multiply \boxed{(90+90+90) \ or \ (90*3) = 270}.

So, we would have to know that was ever this would all add up to be, this would have to be less than 270°

\left[\begin{array}{ccc}\boxed{\boxed{(2.5+5) \\ \\ (2.5*2.5) \\ (2.5-2) \\ (2.5-1) \\}} \\ \\ this \ would \ be \ why \ I \ would \ say \\ that \ this \ would \ be \ the \ answer \end{array}\right]

I truly hope this helps, and also, it's kind of my 
 first time doing this I hope this would be helpful.
~Jurgen
7 0
4 years ago
Find the equation of the line passing through the points 7,2 and 9,1
bija089 [108]

9514 1404 393

Answer:

  y = -1/2x +11/2

Step-by-step explanation:

The slope of the line is ...

  m = (y2 -y1)/(x2 -x1)

  m = (1 -2)/(9 -7) = -1/2

The y-intercept is ...

  b = y -mx

  b = 2 -(-1/2)(7) = 11/2

Then the slope-intercept equation is ...

  y = -1/2x +11/2

_____

<em>Alternative solution</em>

A general form equation for the line can be ...

  (y1 -y2)(x -x1) -(x1 -x2)(y -y1) = 0

  (2 -1)(x -7) -(7 -9)(y -2) = 0

  x-7 +2y -4 = 0

  x +2y -11 = 0 . . . . . general form equation

  x +2y = 11 . . . . . . . standard form equation

Note that we want the x-coefficient to be positive, so we chose the order of the points to make that be the case.

5 0
3 years ago
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