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Ivanshal [37]
3 years ago
15

Shared decision making is always a positive strategy to take? True or false

Business
2 answers:
Bezzdna [24]3 years ago
6 0

I think it's true, for example if you are taking science class and doing a lab then you need to share decision or there is no team work

Arada [10]3 years ago
5 0

False.

It all depends on the situation. Sometimes, shared decision making will be the right approach in order to hear ideas and brainstorm. Other times, having too many opinions will make the decision harder and the leader needs to move forward with what they think will be best.

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Suppose Stuart Company has the following results related to cash flows for 2021: Net Income of $5,600,000 Increase in Accounts P
seropon [69]

1. The statement of cash flows of Stuart Company for the year ended December 31, 2021, is as follows:

Stuart Company

<h3>Statement of Cash Flows</h3>

For the year ended December 31, 2021,        $'000

Net Income                                                     $5,600

Depreciation                                                      1,900

Other Adjustments                                            (800)

Increase in Accounts Payable                           600

Decrease in Accounts Receivable                    900

Increase in Inventory                                        (200)

Net Cash Flow from Operating Activities $8,000

2. The Net Cash Flow from Operating Activities for Stuart Company for 2021 is <u>$8 million</u>.

<h3>What are operating activities' cash flows?</h3>

The cash flows from the operating activities section affect revenues and expenses.

They indicate the cash flows that originate from the regular business activities of the entity.

To prepare the statement of cash flows, the first items to adjust the net income are the non-cash expenses and losses and revenues and gains.

Learn more about the operating activities section at brainly.com/question/25530656

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8 0
2 years ago
Minor Electric has received a special one-time order for 1,500 light fixtures (units) at $5 per unit. Minor currently produces a
Maslowich
The company should accept the special order because it will get an additional profit of $4,000 ($12,500 - $7,500 - $1,000) for the special order. This additional profit amount can be acquired by separating the effect from the special order on each cost and sales of the company's business. The sales should increase by $12,500 ($5 x 2500 unit) amount if the job is taken and the variable cost should increase by $7,500 ($3 x 2500 unit). Lastly, the fixed cost should increase by $1,000 (the new machine).
3 0
3 years ago
Read 2 more answers
Consumer​ surplus:
elena-14-01-66 [18.8K]

Consumer surplus is the difference between the maximum amount the consumer is willing to pay for the price of the good and the price that was actually paid by the consumer or commonly known as the current market price. The price that the consumer is willing to pay is determined by the demand curve in the market.

8 0
4 years ago
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Refer to Exhibit 31-4. If a negative externality exists, then curve __________ represents the marginal social cost curve and the
IrinaK [193]

Answer:

Demand

Consumer interference

Explanation:

The social demand curve represents the benefit of demand to the whole society whereas the normal demand curve represents the benefits to the consumers only. The demand curve represents the social cost curve and the market failure is analyzed by the customer interference.

7 0
3 years ago
Consider the following linear program: Min s.t. 8X + 12Y 1X + 3Y &gt;= 9 2X + 2Y &gt;= 10 6X + 2Y &gt;= 18 A, B &gt;= 0 a. Use t
mihalych1998 [28]

Answer: Graph of (A) (B) and {D) are attached accordingly.

Explanation:

A)

The critical region of the constraints can be seen in the following diagram -

(0,9) (0,5) (0,3) (0,0) (3,0) (5,0) (9,0) The feasible region is shown in white

The intersection points are found by using these equations -

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 48

(9,0) x+3y = 9; y = 0 72

(2,3) 2x+2y = 10; 6x+2y = 18 52

(0,9) 6x+2y = 18; x = 0 108

So, we can see the minimum value of the objective function occurs at point (3,2) and the minimum value of the objective function is = 48.

------------------------------------------------------------------------------------------------------------------------------------------------------------------

B)

When we change the coefficients of the variables in the objective function, the optimal solution may or may not change as the weights (coefficient) are different for each constraints for both the variabls. So, it all depends on the coefficient of the variables in the constraints.

In this case, the optimal solution does not change on changing the coefficient of X from 8 to 6 in the objective function.

The critical region would remain same (as shown below) as it is defined by the constraints and not the objective function.

(0,9) (0,5) (0,3) (0,0) (3,0) (5,0) (9,0) The feasible region is shown in white

However, the optimal value of the objective function would change as shown below-

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 42

(9,0) x+3y = 9; y = 0 54

(2,3) 2x+2y = 10; 6x+2y = 18 48

(0,9) 6x+2y = 18; x = 0 108

So, we can see that the minimum value now has become 42 (which had to change obviously).

-------------------------------------------------------------------------------------------------------------------------------------------------------

C)

Now, when we change the coefficient of the variable Y from 12 to 6, again the critical region would remain same as earlier. But in this case, the optimal solution changes as shown below -

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 36

(9,0) x+3y = 9; y = 0 72

(2,3) 2x+2y = 10; 6x+2y = 18 34

(0,9) 6x+2y = 18; x = 0 54

We can see that the minimum value now occurs at (2,3) which is 34, so both the optimal solution and optimal value have changed in this case.

----------------------------------------------------------------------------------------------------------------------------------------------------------

D)

When we limit the range of the variables as -

4 \leq X \leq 8 \:\: and\:\: 12\leq Y \leq 24,

the critical region now becomes -

So, the new critical points are (4,12), (4,24), (8,24) and (8,12).

So, the values of the objective function at these points can be calculated as -

Vertex Value of Objective

(4,12) 8*4+12*12 = 176

(4,24) 8*4+12*24 = 320

(8,24) 8*8+12*24 = 352

(8,12) 8*8+12*12 = 208

So, the new optimal solution is (4,12) and the optimal value is 176.

if we knew the range of the variables in the part B and C earlier, we could have just said that the optimal solution will not change as the value would have been no longer depended on the coefficients of variables in the constraints.

7 0
4 years ago
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