F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
6π units
Step-by-step explanation:
Given::
Radius = 4
Angle measure of partial circle (θ) = 360° - right angle = 360° - 90° = 270°
Arc length = θ/360 × 2πr
Plug in the values
= 270/360 × 2 × π × 4
= 0.75 × 8 × π
= 6π units
Which only lists multiples of 16? O1,2,4, 8, 16 O 16, 24, 32, 40 O16, 32, 48, 64 O 1,2, 4, 8, 12, 16
schepotkina [342]
Answer:
48 & 68
Step-by-step explanation:
if you multiply the numbers you will see that you get 48 & 68 multiple times
Answer:
6,000
Step-by-step explanation:
Considering the given angle and the given formula, it is found that the percentage error for an angle of 0.02 radians is of 0.0067%.
<h3>What is the percentage angle for an angle?</h3>
For an angle 
, it is given by the following formula:
In this problem, the angle is of 
, hence:
The percentage error for an angle of 0.02 radians is of 0.0067%.
More can be learned about percent error at brainly.com/question/25224978
