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anzhelika [568]
3 years ago
7

A private jet can fly 1,095 miles in 3 hours with a tailwind but only 987 miles in 3 hours into a headwind find the speed of the

jet in still air
Mathematics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

Step-by-step explanation:

We have the following:

x = the speed of the jet in still air.

y = the speed of the wind

we know that the speed is equal to:

v = d / t

therefore the distance would be:

d = v * t

if we replace with the information of the exercise we have:

3 * (x + y) = 1095

3 * (x - y) = 987

we must solve this system of equations, add both equations and we are left:

3 * x + 3 * y = 1095

3 * x - 3 * y = 987

3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987

6 * x = 2082

x = 2082/6 = 347

now to calculate y, we replace:

3 * (347 + y) = 1095

1041 + 3 * y = 1095

3 * y = 1095 - 1041

y = 54/3 = 18

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

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Step-by-step explanation:

3x + (2x + 4) is equivalent to (3x + 2x) + 4

because there is no change of signs taking place as there is no (-) sign in front of the brackets

3x + (2x + 4) | (3x + 2x) + 4

3x + 2x + 4 | 3x + 2x +4

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Given:

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