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Vera_Pavlovna [14]
4 years ago
15

PLEASE HELPPPP

Chemistry
1 answer:
Y_Kistochka [10]4 years ago
7 0

physical, mathematical, and conceptual are the 3 types of models an example of a conceptual model is a model of our solar system or even a rocket a limitation of them is they are not realistic in scale but allow us see arrangements of things. mathematical models could be something like a formula graph charts ect we benefit from the visual steps however the downfall is there's lots of user error and a physical model is something like an atom model it allows to see the thing but it's physical states limits us

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Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following recipe:
sladkih [1.3K]

Answer:

8.59 g

2.25 g

Explanation:

According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-

Moles of Pb(OH)CL is

= \frac{Mass}{Molar\ mass}

= \frac{10.0 g}{259.65g / mol}

= 0.0385 mol

Mass of PbO needed is

= 0.385mol Pb(OH) Cl\times \frac{1 mol PbO}{1molpb (OH) cl} \times \frac{223.2g PbO}{1mol PbO}

After solving the above equation we will get

= 8.59 g

Mass of NaCL needed is

= \frac{1mol\ NaCl}{1molPb\ (OH)Cl} \times \frac{58.45NaCl}{1mol NaCl}

After solving the above equation we will get

= 2.25 g

Therefore we have applied the above formula.

7 0
3 years ago
3) If an electrical appliance has 150.0 V applied causing a current of 2.34 amps, what is the
eimsori [14]

The resistance of the appliance is 64.1 Ω.

<u>Explanation:</u>

As per the Ohm's law, which states that the electric current is in direct proportion to the voltage and is in inverse proportion to the resistance. It is given by the expression as,

V = IR

Where V is the voltage (V) = 150.0 V

I is the current (amps) = 2.34 amps

R is the resistance (ohm) or Ω = ?

Now we have to rearrange the equation to get the resistance as,

$R = \frac{V}{I}

Now we have to plug in the values as,

$ R = \frac{150}{2.34}

   = 64.1 Ω

So the resistance of the appliance is 64.1 Ω.

4 0
4 years ago
Concentration Calculation: Using your Trial 1 ‘difference in final volumes’ data from procedure II and procedure III, and the kn
Digiron [165]

Subtract the mass of the solute from the whole solution volume.

Molarity, percent by mass, and percent by volume are all ways to represent concentration.

By dividing the number of moles by the number of liters of water utilized in the solution, we can compute the molar concentration. Here, for instance, 1.25 L of water has entirely dissolved the acetic acid. In order to determine the molar concentration, which is 0.1332 M, divide 0.1665 moles by 1.25 L. A titration is a method for figuring out the concentration of an unknown solution by using a solution with known concentration.

Finding the concentration for each sample's absorbance on the standard curve is the first step in calculating the sample concentration based on the standard curve. The next step is to multiply the concentration by the dilution factor for each sample.

Learn more about concentration here brainly.com/question/10703427

#SPJ4.

8 0
2 years ago
What is the correct answer please
Anestetic [448]

Answer:

I think it's the second answer --If you increase the acidity..

I hope answer I can answer your question!

7 0
3 years ago
Which of the substances has polar interactions (dipole–dipole forces) between molecules?
Yuki888 [10]

<u>Answer:</u>

CHCl3 has dipole-dipole interactions.

<u>Explanation:</u>

Trichloromethane has a electric dipole moment permanently pointing along the line parallel with the Hydrogen carbon axis.Dipole-dipole interactions are said to be intermolecular force of  attractions that is formed from two permanent dipoles interacting.

These type of interactions  are occurring when one of the partially charged formed molecule are  being attracted to an opposite partially charged molecule  nearby . The molecules align in a state that the positive end of one of the molecule  gets interacting with the negative end of the another molecule.

7 0
3 years ago
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