both A and B are physical properties
Fluorine (F) would be least likely to form a cation out of potassium, fluorine, chlorine, and nitrogen.
- A cation is a positively charged atom (or molecule) that has lost electrons (or electrons).
- The tendency for electropositive elements to lose electrons and produce cations is greater. On the left side of the periodic table, these are often metals.
- Going down a group increases electropositivity, or the propensity to lose electrons and generate cations. and decreases across a period. In the given examples:
- Potassium, K is an alkali metal and will lose electrons readily to form a cation.
- Nitrogen (N), Fluorine (F), and chlorine (Cl) are all nonmetals that prefer to accept electrons and form anions instead. F is the most electronegative i.e. it will gain electrons and form F- rather than F+.
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<span>This is an example of diffusion. The nitrous oxide is moving from an area of higher concentration, down the gradient into the cell, which has a lower concentration. Since the cell doesn't have as much N2O as the surrounding environment, the gas will move inside the cell as a way of attaining equilibrium.</span>
Answer:
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Explanation:
Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.