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ioda
2 years ago
14

A sample of helium gas has a volume of 2.0 L at a pressure of 4.0 atm. What is the volume of gas at 380 mmHg

Chemistry
1 answer:
Lilit [14]2 years ago
5 0
From equation;
P1V1=P2V2
V2=P1V1÷P2
since P2=380mmHg
now;1atm=760mmHg
how about 380mmHg is equal to how many atm?
380×1÷760=0.5atm
P2 now is equal to 0.5atm
back from equation;
P1V1=P2V2
V2=P1V1÷P2
V2=4.0atm×2.0L÷0.5atm
V2=16L
therefore V2=16L.
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The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E
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K will give up an electron more easily than Br.

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From the data given, we see that Br has an E.N value of 3.0 and K has an E.N value of 0.82.

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3 years ago
Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The
yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of N_2 = 8.00 atm

The partial pressure of O_2 = 5.00 atm

K_p = 0.0025

The balanced equilibrium reaction is,

                               N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initial pressure     8.00      5.00            0

At eqm.               (8.00-x) (5.00-x)        2x

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}

Now put all the values in this expression, we get :

0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}

By solving the terms, we get:

x=0.15atm

The equilibrium partial pressure of N_2 = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of N_2 is 7.8 atm.

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3 years ago
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