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ioda
3 years ago
14

A sample of helium gas has a volume of 2.0 L at a pressure of 4.0 atm. What is the volume of gas at 380 mmHg

Chemistry
1 answer:
Lilit [14]3 years ago
5 0
From equation;
P1V1=P2V2
V2=P1V1÷P2
since P2=380mmHg
now;1atm=760mmHg
how about 380mmHg is equal to how many atm?
380×1÷760=0.5atm
P2 now is equal to 0.5atm
back from equation;
P1V1=P2V2
V2=P1V1÷P2
V2=4.0atm×2.0L÷0.5atm
V2=16L
therefore V2=16L.
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Tengo que resolver con procedimiento
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Answer:

Distance = 200 km

Distance = 204 km

Speed = 77 km/h

Time = 21.42 h

Explanation:

Given:

A.

Speed = 100 km/h , Time = 2 h

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Distance

B.

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A.

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B.

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C.

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D.

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6 0
3 years ago
What volume would 0.735 moles of O2 gas occupy at STP
tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

              Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

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