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maksim [4K]
3 years ago
7

Suppose you choose a marble from a bag containing 3 red marbles, 3 white marbles, and 5 blue marbles. You return the first marbl

e to the bag and then choose again. Find P(red and blue). A.6/11 B.15/121 C.15/11 D.8/11
Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

B.15/121

Step-by-step explanation:

  • red-3
  • white-3
  • blue-5

total-11

  • P(red)= 3/11
  • P(blue)=5/11
  • P(red+blue)= 3/11*5/11= 15/121
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Write an equation of a line that passes through (-12, -14) with slope 6.
damaskus [11]

The slope intercept form of a line is y = mx + b

  • m = slope
  • b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

  • y = 6x + b
  • We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

  • -14 = 6(-12) + b

Solve for b to find the y-intercept.

  • -14 = -72 + b
  • 58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

6 0
3 years ago
Work out the value of R. Give your answer in standard form to an appropriate degree of accuracy.
Mumz [18]

Answer:

R = 8,228,571.43 (Approx)

Step-by-step explanation:

Given:

R = x²/y

x = 4.8 x 10⁵

y = 2.8 x 10⁴

Find:

Value of R

Computation:

R = x²/y

R = (4.8 x 10⁵)²/ (2.8 x 10⁴)

R = 23.04 x 10¹⁰ / (2.8 x 10⁴)

R = 8.22857.. x 10⁶

R = 8,228,571.43 (Approx)

4 0
3 years ago
Help me please I’m not sure about this
frutty [35]

easy, 36/6=6

6 people, right?

7 0
3 years ago
Read 2 more answers
If the domain of f (x)=x^2 + 1 to {0,1,2,3}, what is the maximum value of the range?
Naddik [55]
I hope this helps you



x=0 f (0)=0^2+1=1



x=1 f (1)=1^2+1=2



x=2 f (2)=2^2+1=5



x=3 f (3)=3^2+1=10
3 0
3 years ago
Read 2 more answers
Real estate ads suggest that 56 % of homes for sale have​ garages, 27 % have swimming​ pools, and 16 % have both features. ​a) W
Marizza181 [45]

Answer:

a) 0.4

b) 0.28

c) The events are not independent

d) The events are not mutually exclusive

Step-by-step explanation:

Hi!

Lets call:

Gar = {homes with garage}

Pool = {homes with pool},  

A = {homes with pool and garage}  = Gar ∩ Pool

The data we are given is:

P(Gar) = 0.56

P(Pool) = 0.27

P(A) = 0.16

a) B = {homes with garage but not pool}. This set B is the set Gar without set A: B = Gar / A  

P(B) = P(Gar) - P(A) = 0.4

b) This is a conditional probability:

P(Pool | Gar) = P(Gar ∩ Pool) / P(Gar) = 0.16/0.56 = 0.28

c) To be independent events, it must be, by definition:

P(Gar ∩ Pool) = P(Gar) * P(Pool)

0.16 ≠ 0.56*0.27 = 0.15

Then, the events Gar and Pool are not independent

d) Gar and Pool are not mutually exclusive, because there are houses with both pool and garage. We know that because P(A) is not zero.

5 0
3 years ago
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