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4 years ago

Please help me quick!!!

Mathematics

1 answer:

Burka [1]4 years ago

4 0

Answer:

could you send a picture

You might be interested in

The mean per capita income is 20,90820,908 dollars per annum with a standard deviation of 407407 dollars per annum. What is the

LiRa [457]

Answer:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390

Step-by-step explanation:

We define the variable of interest as the per capita income and we know the following properties for this variable:

$\mu=20908$ and $\sigma=407$

We want to find this probability:

$P(20908-28$

We select a sample size of n=55 and we define the z score formula given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

We can find the z score then for 20880 and 20936 and we got:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390

7 0

3 years ago

How do you solve 1/3+1/4?

Otrada [13]

Answer:

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(1/3×4/4)+(1/4×3/3)=?

Complete the multiplication and the equation becomes

4/12+3/12=?

The two fractions now have like denominators so you can add the numerators.

Then:

4+3

12= 7/12

This fraction cannot be reduced.

Therefore:

1/3+1/4=7/12

3 0

3 years ago

Help me please<br>help.me

levacccp [35]

Answer:

The answers of the questions are given below :

a) = 4096
b) = 1.25
3) = m²
4) = r⁴s³
5) = a⁸/b¹²

Step-by-step explanation:

$\large{\tt{\underline{\underline{\red{QUESTION}}}}}$

$\begin{gathered}\footnotesize\boxed{\begin{array}{c|c|c}\bf\underline{Given}&\bf\underline{Solution}&\bf{\underline{Simple\: Form}}\\\\\rule{60pt}{0.5pt} &\rule{70pt}{0.5pt}& \rule{70pt}{0.5pt}\\\\ 1.\: {4}^{6} & & \\\\ 2.\: \bigg(\dfrac{2^6}{5^3} \bigg)& &\\\\ 3. \: \Big({m}^{\frac{2}{3}}\Big)\bull \Big({m}^{\frac{4}{3}}\Big) & &\\\\4. \: \big({r}^{12} {s}^{9}\big)^{ - \frac{1}{3}} &&\\\\ 5.\bigg(\dfrac{a^4}{a^6}\bigg)^{2}& &\end{array}}\end{gathered}$

$\begin{gathered}\end{gathered}$

$\large{\tt{\underline{\underline{\red{SOLUTION}}}}}$

Question. 1

>> 4⁶

$\begin{gathered}\qquad{= 4 \times 4 \times 4 \times 4 \times 4 \times 4} \\ \qquad{= 16 \times 4 \times 4 \times 4 \times 4} \\ \qquad{= 64 \times 4 \times 4 \times 4} \\ \qquad{= 256\times 4 \times 4} \\ \qquad{= 1024 \times 4} \\ \qquad{= 4096} \end{gathered}$

Hence, the answer is 4096.

$\begin{gathered}\end{gathered}$

Question. 2

>> (2⁶/5³)^-⅓

$\begin{gathered} \qquad\implies{\bigg(\frac{2^6}{5^3}\bigg)^{ - \frac{1}{3}}}\\ \\ \qquad\implies{\bigg(\frac{64}{125}\bigg)^{ - \frac{1}{3}}}\\ \\\qquad\implies{\bigg( \frac{1}{\frac{64}{125}}\bigg)^{ \frac{1}{3}}} \\ \\ \qquad\implies{\bigg( 1 \times \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\ \\ \qquad\implies{\bigg( \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\ \\\qquad\implies{\bigg( \sqrt[3]{ \frac{125}{64}}\bigg)} \\ \\ \qquad\implies{\bigg( \dfrac{5}{4} \bigg)} \\ \\ \qquad\implies{\Big( 1.25\Big)}\end{gathered}$

Hence, the answer is 1.25.

$\begin{gathered}\end{gathered}$

Question. 3

>> (m^2/3)•(m^4/3)

$\begin{gathered} \qquad{= \Big({m}^{\frac{2}{3}}\Big) \bull \Big({m}^{ \frac{4}{3}}\Big)} \\ \\ \qquad{= \Big({m}^{\frac{2}{3} + \frac{4}{3}}\Big)} \\ \\ \qquad{= \Big({m}^{\frac{2 + 4}{3}}\Big)} \\ \\ \qquad{= \Big({m}^{\frac{6}{3}}\Big)} \\ \\ \qquad{= \Big({m}^{2}\Big)}\end{gathered}$

Hence, the answer is m².

$\begin{gathered}\end{gathered}$

Question. 4

>> (r¹² s⁹)^⅓

$\begin{gathered} \qquad\implies{\Big( {r}^{12} \: {s}^{9}\Big)^{\frac{1}{3}}}\\\\ \qquad\implies{\Big({r}^{\frac{12}{3} } \: {s}^{\frac{9}{3}}\Big)} \\ \\ \qquad\implies{\Big({r}^{\cancel{\frac{12}{3}}} \: {s}^{\cancel{\frac{9}{3}}}\Big)} \\ \\ \qquad\implies{\Big({r}^{4} \: {s}^{3}\Big)} \end{gathered}$

Hence, the answer is r⁴s³.

$\begin{gathered}\end{gathered}$

Question. 5

>> (a⁴/b⁶)^2

$\begin{gathered} \qquad{ = \Big(\frac{a^4}{b^6}\Big)^{2}} \\ \\ \qquad{ = \Big(\frac{a^{4 \times 2}}{b^{6 \times 2}}\Big)} \\ \\ \qquad{ = \Big(\frac{a^{8}}{b^{12}}\Big)} \end{gathered}$