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kherson [118]
3 years ago
9

Sam sharpens pencils for his after school job. He can sharpen 26 pencils in 6 minutes. If he keeps this rate, how many pencils c

an he sharpen in 15 minutes?​
Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

234

Step-by-step explanation:

multiply 26 x 9

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Is 289 prime? I need this asap (provide factor tree)
antiseptic1488 [7]

Answer: 289 is a semi-prime number that is created by doing 17 times 17. 17 is a prime number though. hope this helps.

Step-by-step explanation:

                           289

                         17    17                

6 0
3 years ago
Find the value of f(–3) and g(3) if f(x) = –6x + 3 and g(x) = 3x + 21x–3.
ryzh [129]

Answer:

f(-3) = 21

g(3) = 69

Step-by-step explanation:

We have been given the following functions;

f(x) = –6x + 3

g(x) = 3x + 21x–3.

To find f(-3) , we simply substitute x = -3 in the function of f(x);

f(-3) = -6(-3) + 3

      = 21

To find g(3) , substitute x = 3 in the function of g(x);

g(3) = 3(3) +21(3) - 3

      = 69

3 0
3 years ago
5.) There are 40
Marina86 [1]
50 dogs and 10 cats
This creates a 5:1 ratio and allows there to be 40 more dogs than cats. 50-10 equals 40
7 0
3 years ago
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
A student worked out at a gym continuously for 50 minutes. The graph shows the remaining percentage of the workout as a linear f
Monica [59]

Small problem....

There is no graph!

ill be happy to solve this if i saw a graph

5 0
2 years ago
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