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jeka94
3 years ago
12

AB has endpoints at (-1, -1) and (-2, -4). Its transformation A'B' has endpoints at (-2, -2) and (-4, -8). What type of transfor

mation occurred? Are lengths of segments affected by this type of transformation? Justify.
A) rotation; no; The lengths of the two segments are the same.

B) reflection; yes; The length of segment A'B' is longer than the original segment AB.

C) dilation by a scale factor of 2; yes; The length of segment A'B' is longer than the original segment AB.

D) dilation by a scale factor of 1/2; The length of segment A'B' is shorter than the original segment AB.

-
(EDIT FOR ANYONE ALSO READING THIS FOR THE ANSWER INCASE NO ONE EVER ANSWERS THIS) The answer was C.
Mathematics
1 answer:
Bad White [126]3 years ago
3 0

The answer is definatly C but if you know the answer why did you ask???

Anyway, hope this helps, and please mark brainliest!!!!!!!!!!!

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Let's break this down into what each piece is.

One flat= one whole= 1

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a) We have 1 flat, 3 rods, and 7 units. Using what we know, we have 1 whole, 3 tenths, and 7 hundredths. So, this is 1 + 0.3+ 0.07. This equals 1.37.

b) 1 flat, 37 units. This is 1 whole, and 37 hundredths. When there are two digits that you want to put in the hundredths place, put the digit furthest to the right in the hundredths place (excluding decimals) and place the rest of the number to the left accordingly. So for us, 37 hundredths would be .37, not .037. Add up 1 and .37, and we have 1.37.

c) 13 rods, 7 units. This is like the last problem. We have two digits wanted to go in the tenths place, but that isn't possible. So, we take the digit all the way to the right and put it in the tenths place (3). Now, we take out remaining digits (1), and put it in the next space to the left. Our rods= 1.3. Now for our units. We have 7, so that equals 0.07. Add it together, and now we have 1.37.

All of the problems equal 1.37. This shows how many ways a number can be represented.

Hope this helped! If it's still confusing, feel free to comment. have a nice day!

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