1. (16,25)-(24,5) the interval it falls from is 25 mph to 5 mph or it decreased by 20 mph.
2. From D (24,5) to E (28,45). The interval of time from point D to point E is 5 mph to 45 mph. or it increased by 40 mph.
3. From B (6,25) to C (16,25) and the constant rate is 25 MPH.
I'm not 100% sure about the everything.
<span>1. Make y the subject
a) 4y=12x+18
y = 3x + 4.5
b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3
2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)
slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1
equation
y = 2.5x + 1
b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)
</span>y= 1/2X + 7
slope = 1/2
slope of line perpendicular = -2
passing through point (3,9)
y = mx + b
9 = -2 (3) + b
b = 15
equation
y = -2x + 15
<h2>Answer:</h2>
8.75 feet
<h2>
Step by step:</h2>
Given that a 12 foot ladder leans against a building seven feet above the ground.
By using trigonometry ratio, the angle between the ladder and the ground will be
SinØ = opposite/ hypothenus
SinØ = 7 / 12
SinØ = 0.58333
Ø = Sin^-1(0.58333)
Ø = 35.69 degree
At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?
Using the same trigonometric ratios
SinØ = opposite/hypothenus
Sin 35.69 = opposite/ 15
Cross multiply
Opposite = 15 × sin 35.69
Opposite = 8.75 feet
Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.
Answer: 7/10
Step-by-step explanation:
2/5+3/10=4/10+3/10=7/10
