Answer:
95% Confidence interval = (23.4,26.2)
Step-by-step explanation:
In this problem we have to develop a 95% CI for the mean.
The sample size is n=49, the mean of the sample is M=24.8 and the standard deviation of the population is σ=5.
We know that for a 95% CI, the z-value is 1.96.
The CI is

Answer:
-4
Step-by-step explanation:
The slope of a line given two points is given by
m = (y2-y1)/(x2-x1)
= (-4-8)/(2 - -1)
= (-4-8)/(2+1)
= -12/3
= -4
Answer:
b) observing every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses.
d) taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch.
Step-by-step explanation:
These are the two options that are most likely to give you a sample that fairly represents the population. In the first case, the sample that you obtain is likely to be a good representation because Main Street is a road where a great variety of people walk. Moreover, 5 pm is also a time that will allow you to see a great number of different people. The second answer will also give you a good sample, as the poll would include all students in the lunch room, which is all students in the school (the whole population).
It’s b because if Mandy goes 18 days and her friend goes 3 times the days she goes.
Answer:
Each hotdog costs $1.65
Each juice drink costs $1.05
Step-by-step explanation:
Let's begin by letting
represent the number of hot dogs and
the number of juice drinks.
The Baxter family bought 6 hot dogs and 4 juices for $14.10.

The Farley family bought 3 hot dogs and 4 juices for $9.15.

Now, we subtract these equations.

Since
has reversed coefficients, it gets eliminated. Now solve for x.



NOW, we find y by substituting x with 1.65 (in either equation).
We'll use the first equation.




= 1.65
= 1.05
represents hotdogs and
represents juice drinks.
Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.
<em> I hope this helps! :)</em>