The sum of n terms of a geometric sequence with first term "a" and common ratio "r" is given by
You have a=21, r=3, so the sum of 10 terms is
The appropriate choice is the 2nd one:
620,004
Answer:
arc HK = 60
Step-by-step explanation:
angle HLK is an inscribed angle and arc HK is the arc it intercepts
an inscribed angle is equal to half the measure of the arc it intercepts
this can also be said as the intercepted arc is equal to twice the measure of the inscribed angle
Hence arc HK = 30 * 2 = 60
Answer:
a = 4,
b = 12
c = 10
d = 15
Step-by-step explanation:
Since the product of each column is equal, therefore,
b*5 = 60
b = 60 ÷ 5 = 12
c*6 = 60
c = 60 ÷ 6 = 10
Since the sum of each column are equal, therefore,
12 + 10 + a = 5 + 6 + d
22 + a = 11 + d
Think of a number you can add to 22, and another number you can add to 11, which will make both sides equal. Add both numbers, whenmultiplied together should give you 60.
Factors of 60 are:
(a, d)
(1, 60) => 22 + a = 11 + d => 22+1 = 11+60 (incorrect)
(2, 30) => 22 + a = 11 + d => 22+2 = 11+30 (incorrect)
(3, 20) => 22 + a = 11 + d => 22+3 = 21+20 (incorrect)
(4, 15) => 22 + a = 11 + d => 22+4 = 11+15 => 26 = 26 [CORRECT]
(5, 12) => 22 + a = 11 + d => 22+5 = 11+12 (incorrect)
(6, 10) => 22 + a = 11 + d => 22+6 = 11+10 (incorrect)
Therefore,
a = 4,
d = 15
Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:
The answer is eight.
Step-by-step explanation:
We know that x is eight. That means we can plug eight in for x. If we do that we get 2^8-5. 8-5 is three, so our problem becomes 2^3, which is 8.
