Answer:
Option 4. 0.05 J
Solution:
As per the question:
Spring constant, k = 10 N/m
Equilibrium position, x = 0.1 m
Now,
The potential energy of the spring is given by:
![U = \frac{1}{2}kx^{2}](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D)
And also from the principle of conservation of energy:
KE = U (1)
where
KE = Maximum Kinetic Energy
U = Potential energy
Thus
KE = U = ![\frac{1}{2}kx^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D)
KE = U = ![0.5\times 10\times 0.1^{2} = 0.05\ J](https://tex.z-dn.net/?f=0.5%5Ctimes%2010%5Ctimes%200.1%5E%7B2%7D%20%3D%200.05%5C%20J)
Answer:
t = 25.5 min
Explanation:
To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.
![t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h](https://tex.z-dn.net/?f=t_1%3D%5Cfrac%7Bx%7D%7Bv_1%7D%3D%5Cfrac%7B150mi%7D%7B65mph%7D%3D2.30h%5C%5C%5C%5Ct_2%3D%5Cfrac%7Bx%7D%7Bv_2%7D%3D%5Cfrac%7B150mi%7D%7B80mph%7D%3D1.875h)
Next, you calculate the difference between both times t1 and t2:
![\Delta t=t_1-t_2=2.30h-1.875h=0.425h](https://tex.z-dn.net/?f=%5CDelta%20t%3Dt_1-t_2%3D2.30h-1.875h%3D0.425h)
This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:
![0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s](https://tex.z-dn.net/?f=0.425h%2A%5Cfrac%7B60min%7D%7B1h%7D%3D25.5min%3D25%5C%20min%5C%20%5C%2030%20s)
hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph
You might see the word alloy described as a "mixture of metals", but that's a little bit misleading because some alloys contain only one metal and it's mixed in with other substances that are nonmetals (cast iron, for example, is an alloy made of just one metal, iron, mixed with one nonmetal, carbon). The best way to think of an alloy is as a material that's made up of at least two different chemical elements, one of which is a metal. The most important metallic component of an alloy (often representing 90 percent or more of the material) is called the main metal, the parent metal, or the base metal. The other components of an alloy (which are called alloying agents) can be either metals or nonmetals and they're present in much smaller quantities (sometimes less than 1 percent of the total). Although an alloy can sometimes be a compound (the elements it's made from are chemically bonded together), it's usually a solid solution (atoms of the elements are simply intermixed, like salt mixed with water).
The weight of the mass is 490 N
Explanation:
The weight of an object is equal to the gravitational force exerted by the Earth on the object, and it is given by the equation
![F=mg](https://tex.z-dn.net/?f=F%3Dmg)
where
m is the mass of the object
g is the acceleration due to gravity
For the object in this problem, the mass is
m 50 kg
While on the Earth's surface, the value of the acceleration of gravity is
![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
Therefore, the weight of the object is:
![W=(50)(9.8)=490 N](https://tex.z-dn.net/?f=W%3D%2850%29%289.8%29%3D490%20N)
Learn more about weight and forces:
brainly.com/question/8459017
brainly.com/question/11292757
brainly.com/question/12978926
#LearnwithBrainly
In physical chemistry or in thermodynamics, the work done on the system or by the system (depending on the sign convention) can be determined in several ways. When assumptions like ideal gas behavior is applied, then the formula for work is
W = Δ(PV)
which is the change of the product of Pressure and Volume. But since it was specified that Pressure is constant, the work could be simplified into
W = PΔV = P(V₂ - V₁)
Since we already know the constant pressure and the volumes of the ideal gas before and after the change, we could now solve for work. But let's establish first the units of work which is in Joules. When simplified, Joules is equal to m³*Pa. So, we first change the unit of pressure from atm to Pascals ( 1 atm = 101,325 Pa) and the unit of volume from liters to m³ (1 m³ = 1000 L),
1.5 atm * 101325 Pa/1 atm = 151987.5 Pa
15 L * 1 m³/1000 L = 0.015 m³
35 L * 1 m³/1000 L = 0.035 m³
Then, they are now ready for substitution,
W = 151987.5 Pa (0.035 m³ - 0.015 m³)
W = 3,039.75 Joules