Question

What is the heat needed to raise the temperature of 24.7 kg silver from 14.0 degrees celsius to 30.0 degrees celsius? specific heat capacity of silver is 236 j/(kg * c°). 5.93 e 4 j 8.18 e 4 j 9.32 e 4 j 11.6 e 4 j 17.5 e 4 j?

Answer 1

The amount of heat needed to increase the temperature of a substance by $\Delta T$ is given by
$Q=m C_s \Delta T$
where
m is the mass of the substance
$C_s$ is its specific heat capacity
$\Delta T$ is the increase of temperature

The sample of silver of our problem has a mass of $m=24.7 kg$. Its specific heat capacity is $C_s = 236 J/g^{\circ}C$ and the increase in temperature is
$\Delta T=30.0^{\circ}-14.0^{\circ}C=16.0^{\circ}C$

Therefore, the amount of heat needed is
$Q=mC_s \Delta T=(24.7 kg)(236 J/g^{\circ}C)(16.0^{\circ}C)=9.32 \cdot 10^4 J$