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sleet_krkn [62]
3 years ago
6

A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the spee

d of the train relative to the girl?
Physics
2 answers:
sineoko [7]3 years ago
6 0

Answer:

velocity of the train with respect to girl is 85 m/s

Explanation:

As we know that girl is moving towards the train in front of it with speed

v_1 = 10 m/s

also we know that the speed of the train towards the girl is

v_2 = 75 m/s

Now we know that relative velocity of the train with respect to girl is given as

\vec v_{tg} = \vec v_t - \vec v_g

here let say the velocity of train is positive while girl is running opposite to train so its velocity is negative

\vec v_{tg} = 75 m/s - (-10 m/s)

\vec v_{tg} = 85 m/s

dimulka [17.4K]3 years ago
5 0
We can take as positive direction the direction of the train, and as negative direction the direction of the girl. The speed of the train relative to the girl will be given by the difference between the two velocities:
v' = v_t - v_g
which means
v'=75 m/s - (-10 m/s)=85 m/s
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12.Two ice skaters are initially at rest. The 78.2 kg male ice skater pushes his 48.5 kg female partner forward and away from hi
NeTakaya

Answer:

The male skater's velocity is 13.71 m/s.

Explanation:

From the law of conservation of momentum:

m1u1 = (m1 + m2)u2

m1 is the mass of the male skater = 78.2 kg

m2 is the mass of the female skater = 48.5 kg

u1 is the velocity of the male skater as a result of the push

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3 years ago
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A group of students are provided with three objects all of the same mass and radius. The objects include a solid cylinder, a thi
SOVA2 [1]

Answer:

Sphere, cylinder    hoop

Explanation:

To analyze Which student is right it is best to propose the solution of the problem. Let's look for the speed of the center of mass. Let's use the concept of mechanical energy

In the highest part of the ramp

     Em₀ = U = mg y

In the lowest part

Here the energy has part of translation and part of rotation

      E_{mf}  = K_{T} + K_{R}

      E_{mf}  = ½ m v_{cm}² + ½ I w²

Where I is the moment of inertia of the body and w the angular velocity that relates to the velocity of the center of mass

     v_{cm} = w r

    w = v_{cm} / r

Let's replace

   E_{mf} = ½ I (v_{cm} / r)²

Energy is conserved

   mg y = ½ m v_{cm}² + ½ I v_{cm}² / r2

   ½ (m + I / r²) v_{cm}² = m g y

   ½ (1 + I / m r²) v_{cm}² = g y

   v_{cm} = √ [2gy / (1 + I / mr²)]

This is the velocity of the center of mass of the bodies, as they all have the same radius with comparing this point is sufficient. Now let's use the speed definition

   v = d / t

   t = d / v

   t = d / (√ [2gy / (1 + I / mr²)])

   t = (d / √ 2gy) √(1 + I / m r²)

Therefore we see that time is proportional to the square root. All quantities are constant and the one that varies is the moment of inertia.

The moments of inertia of

Sphere is   Is = 2/5 M r²

Cylinder    Ic = ½ M r²

Hoop         Ih = M r²

Let's replace each one and calculate the time

Sphere

    ts = (d / √2gy) √ (1 + 2/5 Mr² / mr²)

    ts = (d / √ 2gy) √ (1 +2/5) = (d / √ 2gy) √(1.4)

    ts = (d / √ 2gy)      1.1

Cylinder

    tc = (d / √2gy) √ (1 + 1/2 Mr² / Mr²)

    tc = (d / √2gy) √ (1 + ½) = (d / √ 2gy) √ 1.5

    tc = (d / √ 2gy)    1.2

Hoop

    th = (d / √2gy) √ (1 + mr² / mr²)

    th = (d / √2gy) √(1 + 1) = (d / √ 2gy) √ 2

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We have the results for the time the body that arrives the fastest is the sphere and the one that is the most hoop. Therefore the correct answer is

         ts < tc < th

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5 0
3 years ago
A child weighing 200 N is being held back in a swing by a horizontal force of 125 N, as shown in the image. What is the tension
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Answer:

75

Explanation:

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What multiple of the time constant τ gives the time taken by an initially uncharged capacitor in an RC series circuit to be char
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Answer:

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In our case we are asked that the load be 94.5%, this means that

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Let's replace and calculate

    q/q₀ = 1 - e (-t/τ₀)

    0.945 = 1 - e (-t/τ₀)

    (-t /τ₀) = ln (1 -0.945) = ln (0.055)

    t / τ₀ = 2.9

the time constant has to be multiplied by approximately three for this charge

5 0
4 years ago
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